Advertisements
Advertisements
Question
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
2x - 3y = 6
`x/(2) + y/(3) = 1`
Advertisements
Solution
To draw the graph of 2x - 3y = 6 and `x/(2) + y/(3) = 1` follows the steps:
First prepare a table as below:
| X | -1 | 0 | 1 |
| Y = `(2)/(3) xx 2` | `-(8)/(3)` | -2 | `-(4)/(3)` |
| Y = `-(3)/(2) xx + 3` | `(9)/(2)` | 3 | `(3)/(2)` |
Now sketch the graph as shown:
From the graph it can verify that the lines are perpendicular.
APPEARS IN
RELATED QUESTIONS
Draw the graph for the linear equation given below:
x - 5 = 0
Draw the graph for the linear equation given below:
3y + 5 = 0
Draw the graph for the linear equation given below:
y = - x
Draw the graph for the linear equation given below:
y = `(2x)/(3) - 1`
Draw the graph for the linear equation given below:
y = - x + 4
Draw the graph for the linear equation given below:
y = `4x - (5)/(2)`
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
y = 3x - 1
y = 3x + 2
On the same graph paper, plot the graphs of y = 2x - 1, y = 2x and y = 2x + 1 from x = - 2 to x = 4. Are the graphs (lines) drawn parallel to each other?
Draw a graph of each of the following equations: x + y - 3 = 0
Draw a graph of the equation 2x - 3y = 15. From the graph find the value of:
(i) x, when y = 3
(ii) y, when x = 0
