Advertisements
Advertisements
Question
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
y = 3x - 1
y = 3x + 2
Advertisements
Solution
To draw the graph of y = 3x - 1 and y = 3x + 2 follows the steps:
First, prepare a table as below:
| X | - 1 | 0 | 1 |
| Y = 3x -1 | - 4 | - 1 | 2 |
| Y = 3x + 2 | - 1 | 2 | 5 |
Now sketch the graph as shown
:
From the graph it can verify that the lines are parallel.
APPEARS IN
RELATED QUESTIONS
Draw the graph of the equation given below.
x + y = 2
Draw the graph for the linear equation given below:
x = 3
Draw the graph for the linear equation given below:
3y + 5 = 0
Draw the graph for the linear equation given below:
y = `(2x)/(3) - 1`
Draw the graph for the linear equation given below:
`(x - 1)/(3) - (y + 2)/(2) = 0`
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
2x - 3y = 6
`x/(2) + y/(3) = 1`
On the same graph paper, plot the graph of y = x - 2, y = 2x + 1 and y = 4 from x= - 4 to 3.
Draw the graph of equation 3x – 4y = 12. Use the graph drawn to find:
- y1, the value of y, when x = 4.
- y2, the value of y, when x = 0.
Draw a graph of each of the following equations: 2(x - 5) = `(3)/(4)(y - 1)`
Draw a graph of each of the following equations: y = `(3)/(5) x - 1`
