Advertisements
Advertisements
Question
On the same graph paper, plot the graph of y = x - 2, y = 2x + 1 and y = 4 from x= - 4 to 3.
Advertisements
Solution
First, prepare a table as follows:
| X | -1 | 0 | 1 |
| Y = x - 2 | -3 | -2 | -1 |
| Y = 2x + 1 | -1 | 1 | 3 |
| Y = 4 | 4 | 4 | 4 |
Now the graph can be drawn as follows:
APPEARS IN
RELATED QUESTIONS
Draw the graph for the linear equation given below:
x - 5 = 0
Draw the graph for the linear equation given below:
y - 2 = 0
Draw the graph for the linear equation given below:
y = 2x + 3
Draw the graph for the each linear equation given below:
y = `(3x)/(2) + (2)/(3)`
Draw the graph for the equation given below:
`(2x - 1)/(3) - (y - 2)/(5) = 0`
For the linear equation, given above, draw the graph and then use the graph drawn (in the following case) to find the area of a triangle enclosed by the graph and the co-ordinates axes:
7 - 3 (1 - y) = -5 + 2x
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
3x + 4y = 24
`x/(4) + y/(3) = 1`
Draw a graph of each of the following equations: x + 6y = 15
Draw a graph of each of the following equations: y = `(3)/(5) x - 1`
Draw the graph of the lines y = x + 2, y = 2x - 1 and y = 2 from x = -3 to 4, on the same graph paper. Check whether the lines drawn are parallel to each other.
