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प्रश्न
On the same graph paper, plot the graph of y = x - 2, y = 2x + 1 and y = 4 from x= - 4 to 3.
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उत्तर
First, prepare a table as follows:
| X | -1 | 0 | 1 |
| Y = x - 2 | -3 | -2 | -1 |
| Y = 2x + 1 | -1 | 1 | 3 |
| Y = 4 | 4 | 4 | 4 |
Now the graph can be drawn as follows:
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संबंधित प्रश्न
Draw the graphs of the following equations on the same system of co-ordinates. Write the co-ordinates of their points of intersection.
x + 4 = 0, y - 1 = 0, 2x + 3 = 0, 3y - 15 = 0
Draw the graph of the equation given below.
2x + y = 1
Draw the graph for the linear equation given below:
x = 3
Draw the graph for the linear equation given below:
2x - 7 = 0
Draw the graph for the linear equation given below:
y = - x
Draw the graph for the linear equation given below:
x + 2y = 0
Draw the graph for the linear equation given below:
4x - y = 0
Draw the graph for the equation given below:
3x + 2y = 6
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
y = 3x - 1
y = 3x + 2
Draw the graph of the lines y = x + 2, y = 2x - 1 and y = 2 from x = -3 to 4, on the same graph paper. Check whether the lines drawn are parallel to each other.
