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प्रश्न
On the same graph paper, plot the graph of y = x - 2, y = 2x + 1 and y = 4 from x= - 4 to 3.
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उत्तर
First, prepare a table as follows:
| X | -1 | 0 | 1 |
| Y = x - 2 | -3 | -2 | -1 |
| Y = 2x + 1 | -1 | 1 | 3 |
| Y = 4 | 4 | 4 | 4 |
Now the graph can be drawn as follows:
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संबंधित प्रश्न
Draw the graph for the linear equation given below:
x = 3
Draw the graph for the linear equation given below:
y = 4
Draw the graph for the linear equation given below:
y = 0
Draw the graph for the linear equation given below:
y = - 2x
Draw the graph for the equation given below:
2x - 5y = 10
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
y = 3x - 1
y = 3x + 2
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
y = x - 3
y = - x + 5
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
2x - 3y = 6
`x/(2) + y/(3) = 1`
Draw the graph of equation 3x – 4y = 12. Use the graph drawn to find:
- y1, the value of y, when x = 4.
- y2, the value of y, when x = 0.
Draw a graph of the equation 5x - 3y = 1. From the graph find the value of:
(i) x, when y = 8
(ii) y, when x = 2
