Advertisements
Advertisements
प्रश्न
On the same graph paper, plot the graphs of y = 2x - 1, y = 2x and y = 2x + 1 from x = - 2 to x = 4. Are the graphs (lines) drawn parallel to each other?
Advertisements
उत्तर
First, prepare a table as follows:
| X | -1 | 0 | 1 |
| Y = 2x - 1 | -3 | -1 | 1 |
| Y = 2x | -2 | 0 | 2 |
| Y = 2x + 1 | -1 | 1 | 3 |
Now the graph can be drawn as follows:
The lines are parallel to each other.
APPEARS IN
संबंधित प्रश्न
Draw the graph of the equation given below.
x + y = 2
Draw the graph for the linear equation given below:
y = 4
Draw the graph for the linear equation given below:
3y + 5 = 0
Draw the graph for the linear equation given below:
2x - 3y = 4
Draw the graph for the linear equation given below:
x - 3 = `(2)/(5)(y + 1)`
For the linear equation, given above, draw the graph and then use the graph drawn (in the following case) to find the area of a triangle enclosed by the graph and the co-ordinates axes:
7 - 3 (1 - y) = -5 + 2x
Find if the following points are collinear or not by using a graph:
(i) (-2, -1), (0, 3) and (1, 5)
(ii) (1, 3), (-2, -4) and (3, 5)
(iii) (2, -1), (2, 5) and (2, 7)
(iv) (4, -1), (-5, -1) and (3, -1)
Draw a graph of each of the following equations: x + 6y = 15
Draw a graph of each of the following equations: x = -3y
Draw a graph of the equation 2x + 3y + 5 = 0, from the graph find the value of:
(i) x, when y = -3
(ii) y, when x = 8
