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प्रश्न
Draw a graph of each of the following equations: 2(x - 5) = `(3)/(4)(y - 1)`
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उत्तर
2(x - 5) = `(3)/(4)(y - 1)`
⇒ 8(x - 5) = 3(y - 1)
⇒ 8x - 40 = 3y - 3
⇒ 3y = 8x - 40 + 3
⇒ 3y = 8x - 37
y = `(8x - 37)/(3)`
When x = 2, = `(8(2) - 37)/(3)` = -7
When x = 5, y = `(8(5) - 37)/(3)` = 1
When x = -1, y = `(8(-1) - 37)/(3)` = -15
| x | 2 | 5 | -1 |
| y | -7 | 1 | -15 |
Plotting the points (2, -7), (5, 1) and (-1, -15), we get a line AB as shown in the figure.
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संबंधित प्रश्न
Draw the graph for the linear equation given below:
x - 5 = 0
Draw the graph for the linear equation given below:
5x+ y = 0.
Draw the graph for the linear equation given below:
4x - y = 0
Draw the graph for the linear equation given below:
y = 2x + 3
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
2x - 3y = 6
`x/(2) + y/(3) = 1`
Draw the graph of equation x + 2y - 3 = 0. From the graph, find:
(i) x1, the value of x, when y = 3
(ii) x2, the value of x, when y = - 2.
Find if the following points are collinear or not by using a graph:
(i) (-2, -1), (0, 3) and (1, 5)
(ii) (1, 3), (-2, -4) and (3, 5)
(iii) (2, -1), (2, 5) and (2, 7)
(iv) (4, -1), (-5, -1) and (3, -1)
Draw a graph of each of the following equations: x = -3y
Draw a graph for each of the following equations and find the coordinates of the points where the line drawn meets the x-axis and y-axis: `(2x)/(5) + y/(2)` = 1
Draw the graph of the lines y = x + 2, y = 2x - 1 and y = 2 from x = -3 to 4, on the same graph paper. Check whether the lines drawn are parallel to each other.
