Advertisements
Advertisements
प्रश्न
Draw a graph of each of the following equations: 2(x - 5) = `(3)/(4)(y - 1)`
Advertisements
उत्तर
2(x - 5) = `(3)/(4)(y - 1)`
⇒ 8(x - 5) = 3(y - 1)
⇒ 8x - 40 = 3y - 3
⇒ 3y = 8x - 40 + 3
⇒ 3y = 8x - 37
y = `(8x - 37)/(3)`
When x = 2, = `(8(2) - 37)/(3)` = -7
When x = 5, y = `(8(5) - 37)/(3)` = 1
When x = -1, y = `(8(-1) - 37)/(3)` = -15
| x | 2 | 5 | -1 |
| y | -7 | 1 | -15 |
Plotting the points (2, -7), (5, 1) and (-1, -15), we get a line AB as shown in the figure.
APPEARS IN
संबंधित प्रश्न
Draw the graphs of the following equations on the same system of co-ordinates. Write the co-ordinates of their points of intersection.
x + 4 = 0, y - 1 = 0, 2x + 3 = 0, 3y - 15 = 0
Draw the graph for the linear equation given below:
y + 6 = 0
Draw the graph for the linear equation given below:
3x + 2y = 0
Draw the graph for the linear equation given below:
y = - x + 4
For the linear equation, given above, draw the graph and then use the graph drawn (in the following case) to find the area of a triangle enclosed by the graph and the co-ordinates axes:
3x − (5 − y) = 7
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
3x + 4y = 24
`x/(4) + y/(3) = 1`
The graph of 3x + 2y = 6 meets the x=axis at point P and the y-axis at point Q. Use the graphical method to find the co-ordinates of points P and Q.
Draw a graph of each of the following equations: x + 6y = 15
Draw a graph of each of the following equations: x + y - 3 = 0
Draw a graph of each of the following equations: `(x - 2)/(3) - (y + 1)/(2)` = 0
