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प्रश्न
Draw the graph of equation 3x – 4y = 12. Use the graph drawn to find:
- y1, the value of y, when x = 4.
- y2, the value of y, when x = 0.
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उत्तर
First, prepare a table as follows:
| X | –1 | 0 | 1 |
| Y | `-(15)/(4)` | – 3 | `-(9)/(4)` |
The graph of the equation can be drawn as follows:
From the graph, it can verify that
If x = 4 the value of y = 0
If x = 0 the value of y = –3.
संबंधित प्रश्न
Draw the graph of the equation given below.
x + y = 2
Draw the graph for the linear equation given below:
x = 3
Draw the graph for the linear equation given below:
x - 5 = 0
Draw the graph for the linear equation given below:
y = 4
Draw the graph for the linear equation given below:
y + 6 = 0
Draw the graph for the linear equation given below:
2y - 5 = 0
Draw the graph for the linear equation given below:
y = `(2x)/(3) - 1`
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
y = 3x - 1
y = 3x + 2
Draw the graph of equation `x/(4) + y/(5) = 1` Use the graph drawn to find:
(i) x1, the value of x, when y = 10
(ii) y1, the value of y, when x = 8.
Draw a graph of each of the following equations: 5x + 2y = 16
