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प्रश्न
Draw the graph for the linear equation given below:
y + 6 = 0
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उत्तर
First, prepare a table as follows:
| x | - 1 | 0 | 1 |
| y | - 6 | - 6 | - 6 |
Thus the graph can be drawn as follows:
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संबंधित प्रश्न
Draw the graphs of the following equations on the same system of co-ordinates. Write the co-ordinates of their points of intersection.
x + 4 = 0, y - 1 = 0, 2x + 3 = 0, 3y - 15 = 0
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x + 3 = 0
Draw the graph for the linear equation given below:
y = - 2x
Draw the graph for the linear equation given below:
x - 3 = `(2)/(5)(y + 1)`
Draw the graph for the equation given below:
`(1)/(2) x + (2)/(3) y = 5`.
Draw the graph for the equation given below:
`(2x - 1)/(3) - (y - 2)/(5) = 0`
For the linear equation, given above, draw the graph and then use the graph drawn (in the following case) to find the area of a triangle enclosed by the graph and the co-ordinates axes:
3x − (5 − y) = 7
Draw a graph of each of the following equations: x + 6y = 15
Draw a graph of the equation 5x - 3y = 1. From the graph find the value of:
(i) x, when y = 8
(ii) y, when x = 2
Draw the graph of the lines represented by the equations 3x - 2y = 4 and x + y = 3 on the same graph. Find the coordinates of the point where they intersect. State, whether the lines are perpendicular to each other.
