Advertisements
Advertisements
प्रश्न
Draw the graph of the equation given below.
3x - y = 0
Advertisements
उत्तर
The equation of the given line is 3x − y = 0.
∴ 3x − y = 0
⇒ y = 3x ...(1)
Putting x = 0 in (1), we get
y = 3 × 0
y = 0
Putting x = 1 in (1), we get
y = 3 × 1
y = 3
Putting x = −1 in (1), we get
y = 3 × (−1)
y = −3
Putting x = 2 in (1), we get
y = 3 × 2
y = 6
These values can be represented in the table in the form of ordered pairs as follows:
| x | 0 | 1 | -1 | 2 |
| y | 0 | 3 | -3 | 6 |
| (x, y) | (0, 0) | (1, 3) | (-1, -3) | (2, 6) |

The line is the graph of the equation 3x − y = 0.
APPEARS IN
संबंधित प्रश्न
Draw the graph for the linear equation given below:
x = 3
Draw the graph for the linear equation given below:
3y + 5 = 0
Draw the graph for the linear equation given below:
2y - 5 = 0
Draw the graph for the linear equation given below:
y = 3x
Draw the graph for the linear equation given below:
y = - x
Draw the graph for the linear equation given below:
y = x
Draw the graph for the linear equation given below:
x = - 2y
Draw the graph for the linear equation given below:
y = 2x + 3
Draw the graph for the each linear equation given below:
y = `(3x)/(2) + (2)/(3)`
Draw the graph for the linear equation given below:
`(x - 1)/(3) - (y + 2)/(2) = 0`
Draw the graph for the linear equation given below:
x + 5y + 2 = 0
Draw the graph for the equation given below:
3x + 2y = 6
Draw the graph for the equation given below:
`(1)/(2) x + (2)/(3) y = 5`.
For the linear equation, given above, draw the graph and then use the graph drawn (in the following case) to find the area of a triangle enclosed by the graph and the co-ordinates axes:
3x − (5 − y) = 7
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
3x + 4y = 24
`x/(4) + y/(3) = 1`
On the same graph paper, plot the graphs of y = 2x - 1, y = 2x and y = 2x + 1 from x = - 2 to x = 4. Are the graphs (lines) drawn parallel to each other?
Draw the graph of equation 3x – 4y = 12. Use the graph drawn to find:
- y1, the value of y, when x = 4.
- y2, the value of y, when x = 0.
Draw a graph of each of the following equations: 3x - 2y = 6
Draw a graph of each of the following equations: y = `(3)/(5) x - 1`
Draw the graph of the lines represented by the equations 5y = 3x + 1 and y = 2x + 3 on the same graph. Find the coordinates of the point where they intersect.
