Advertisements
Advertisements
प्रश्न
For the linear equation, given above, draw the graph and then use the graph drawn (in the following case) to find the area of a triangle enclosed by the graph and the co-ordinates axes:
3x − (5 − y) = 7
Advertisements
उत्तर
First draw the graph as follows:
Simplify the given equation
3x − (5 − y) = 7
3x − 5 + y = 7
3x + y = 12
To plot the graph, we need x-intercept and y-intercept.
When y = 0:
3x = 12 ⟹ x = 4
So, the x-intercept = (4, 0)
When x = 0:
y = 12
So, the y-intercept = (0, 12)
O(0, 0), A(4, 0), B(0, 12)
Area of triangle OAB:
Area `= 1/2` × base × height
Base = OA = 4 units
Height = OB = 12 units
Area `= 1/2` × 4 × 12
= 24
APPEARS IN
संबंधित प्रश्न
Draw the graph for the linear equation given below:
y = 4
Draw the graph for the linear equation given below:
y = - 2x
Draw the graph for the equation given below:
2x - 5y = 10
Draw the graph for the equation given below:
`(2x - 1)/(3) - (y - 2)/(5) = 0`
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
y = 3x - 1
y = 3x + 2
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
2x - 3y = 6
`x/(2) + y/(3) = 1`
On the same graph paper, plot the graphs of y = 2x - 1, y = 2x and y = 2x + 1 from x = - 2 to x = 4. Are the graphs (lines) drawn parallel to each other?
Draw a graph of each of the following equations: y = `(5)/(2) xx + (2)/(5)`
Draw the graph of the lines represented by the equations x + y = 4 and 2x - y = 2 on the same graph. Find the coordinates of the point where they intersect
Draw the graph of the lines represented by the equations 2x - y = 8 and 4x + 3y = 6 on the same graph. Find the co-ordinates of the point where they intersect.
