Advertisements
Advertisements
प्रश्न
Draw the graph for the linear equation given below:
y = `4x - (5)/(2)`
Advertisements
उत्तर
First prepare a table as follows:
| x | -1 | 0 | 1 |
| y | `-(13)/(2)` | `-(5)/(2)` | `(3)/(2)` |
Thus the graph can be drawn as follows:
APPEARS IN
संबंधित प्रश्न
Draw the graph for the linear equation given below:
x - 5 = 0
Draw the graph for the linear equation given below:
2x - 7 = 0
Draw the graph for the linear equation given below:
y = 4
Draw the graph for the linear equation given below:
3y + 5 = 0
For the linear equation, given above, draw the graph and then use the graph drawn (in the following case) to find the area of a triangle enclosed by the graph and the co-ordinates axes:
7 - 3 (1 - y) = -5 + 2x
Draw a graph of each of the following equations: x + 6y = 15
Draw a graph of each of the following equations: x = -3y
Draw a graph of each of the following equations: 2(x - 5) = `(3)/(4)(y - 1)`
Draw a graph of each of the following equations: y = `(3)/(5) x - 1`
Draw a graph for each of the following equations and find the coordinates of the points where the line drawn meets the x-axis and y-axis: `(2x)/(5) + y/(2)` = 1
