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Question
Draw a graph of each of the following equations: `(x - 2)/(3) - (y + 1)/(2)` = 0
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Solution
`(x - 2)/(3) - (y + 1)/(2)` = 0
⇒ `(x - 2)/(3) - (y + 1)/(2)`
⇒ 2(x - 2) = 3(y + 1)
= 2x - 4 = 3y + 3
⇒ 3y = 2x - 7
⇒ y = `(2x - 7)/(3)`
When x = 2, y = `(2(2) - 7)/(3)` = -1
When x = -1, y = `(2(-1) - 7)/(3)` = -3
When x = -2.5, y = `(2(-2.5) - 7)/(3)` = 4
| x | 2 | -1 | -2.5 |
| y | -1 | -3 | -4 |
Plotting the points (2, -1), (-1, -3) and (-2.5, -4), we get a line AB as shown in the figure.
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