Question

Draw the graphs of the following equations on the same system of co-ordinates. Write the co-ordinates of their points of intersection.

x + 4 = 0, y - 1 = 0, 2x + 3 = 0, 3y - 15 = 0

Answer 1

∴ x + 4 = 0

⇒ x = −4

x = −4 is the equation of the line parallel to Y-axis at a distance of 4 units from it to its left.

∴ y − 1 = 0 

⇒ y = 1

y = 1 is the equation of the line parallel to X-axis at a distance of 1 unit and above the X-axis. 

∴ 2x + 3 = 0

⇒ x = `-3/2`

`x = - 3/2` is the equation of the line parallel to Y-axis at a distance of `3/2` units from it to its left.

∴ 3y − 15 = 0 

⇒ y = `15/3`

⇒ y = 5

y = 5 is the equation of the line parallel to X-axis at a distance of 5 units and above the X-axis. 

It can be seen from the figure that the co-ordinates of the points of intersection are `(-3/2 , 1), (-3/2 , 5),(-4,5)  "and"  (-4,1)`.