Advertisements
Advertisements
प्रश्न
In square ABCD, P and Q are mid-point of AB and CD respectively. If AB = 8cm and PQand BD intersect at O, then find area of ΔOPB.
Advertisements
उत्तर
Given: Here from the given question we get
(1) ABCD is a square,
(2) P is the midpoint of AB
(3) Q is the midpoint of CD
(4) PQ and BD intersect at O.
(5) AB = 8cm
To find : Area of ΔOPB
Calculation: Since P is the midpoint of AB,
`BP = 1/2 (AB) `
= 1/2 (8)`
= 4 cm
BP = 4cm ……(1)
Area of triangle = `1/2 `× base × height
Area of ΔOPB = `1/2` × BP × PO (from 1)
` = 1/2 × 4 × (PO = 1/2 AD , APQD ` is a rectangle)
`= 1/2 × 16 `
Area of ΔOPB = 8 cm2
Hence we get the Area of ΔOBP = 8 cm2
APPEARS IN
संबंधित प्रश्न
Compute the area of trapezium PQRS is Fig. below.
ABCD is a parallelogram whose diagonals AC and BD intersect at O. A line through O
intersects AB at P and DC at Q. Prove that ar (Δ POA) = ar (Δ QOC).
In below fig., PSDA is a parallelogram in which PQ = QR = RS and AP || BQ || CR. Prove
that ar (Δ PQE) = ar (ΔCFD).
ABCD is a parallelogram. P is any point on CD. If ar (ΔDPA) = 15 cm2 and ar (ΔAPC) = 20 cm2, then ar (ΔAPB) =
In the given figure, ABCD and FECG are parallelograms equal in area. If ar (ΔAQE) = 12 cm2, then ar (||gm FGBQ) =
Length of a rectangle is 30 m and its breadth is 20 m. Find the increase in its area if its length is increased by 10 m and its breadth is doubled.
By counting squares, estimate the area of the figure.
Look at a 10 rupee note. Is its area more than hundred square cm?
In the following figure, the area of parallelogram ABCD is ______.
An engineer who plans to build a compound wall on all sides of a house must find the area of the compound.
