Advertisements
Advertisements
प्रश्न
Find the area of a rectangle whose length = 8.5 m breadth = 5 m.
Advertisements
उत्तर
length = 8.5 m breadth = 5 m
⇒ Area of the rectangle = Length × breadth
= 8.5 m × 5 m
= 42.5 m2
APPEARS IN
संबंधित प्रश्न
In the below Fig, ABC and ABD are two triangles on the base AB. If line segment CD is
bisected by AB at O, show that ar (Δ ABC) = ar (Δ ABD)
If P is any point in the interior of a parallelogram ABCD, then prove that area of the
triangle APB is less than half the area of parallelogram.
ABC is a triangle in which D is the mid-point of BC. E and F are mid-points of DC and AErespectively. IF area of ΔABC is 16 cm2, find the area of ΔDEF.
In the given figure, ABCD is a parallelogram. If AB = 12 cm, AE = 7.5 cm, CF = 15 cm, then AD =
The table given below contains some measures of the rectangle. Find the unknown values.
| Length | Breadth | Perimeter | Area |
| 13 cm | ? | 54 cm | ? |
Altogether how many squares can be arranged on it?
Find the area of the following figure by counting squares:
Find the area of the following figure by counting squares:
Find the area of the following figure by counting squares:
Find the area of the following figure by counting squares:
