Advertisements
Advertisements
प्रश्न
Find the area of a rectangle whose length = 3.6 m breadth = 90 cm
Advertisements
उत्तर
length = 3.6 m breadth = 90 cm
⇒ Area of the rectangle = Length × breadth
= 3.6 m × 0.9 m ...`[90 "cm" = 90/100 "m" = 0.9 "m"]`
= 3.24 m2
APPEARS IN
संबंधित प्रश्न
A point D is taken on the side BC of a ΔABC such that BD = 2DC. Prove that ar(Δ ABD) =
2ar (ΔADC).
Two parallelograms are on the same base and between the same parallels. The ratio of their areas is
A triangle and a parallelogram are on the same base and between the same parallels. The ratio of the areas of triangle and parallelogram is
The area of the figure formed by joining the mid-points of the adjacent sides of a rhombus with diagonals 16 cm and 12 cm is
The perimeter of a triangle ABC is 37 cm and the ratio between the lengths of its altitudes be 6: 5: 4. Find the lengths of its sides.
Let the sides be x cm, y cm, and (37 - x - y) cm. Also, let the lengths of altitudes be 6a cm, 5a cm, and 4a cm.
The medians of a triangle ABC intersect each other at point G. If one of its medians is AD,
prove that:
(i) Area ( ΔABD ) = 3 x Area ( ΔBGD )
(ii) Area ( ΔACD ) = 3 x Area ( ΔCGD )
(iii) Area ( ΔBGC ) = `1/3` x Area ( ΔABC ).
Find the area of a rectangle whose length and breadth are 25 m and 16 cm.
The diagonal of a rectangular board is 1 m and its length is 96 cm. Find the area of the board.
How many tiles like the triangle given here will fit in the white design?
Area of design = ________ square cm
Cheggu’s wife asked him to make a circle with the wire. She knew it had an area of 800 square meters.
- Why did Cheggu not choose a rectangle? Explain.
