Advertisements
Advertisements
प्रश्न
Compute the area of trapezium PQRS is Fig. below.

Advertisements
उत्तर
We have
ar (trap PQRS) = ar (rect PSRT) + are a (ΔQRT)
⇒ ar (trap .PQRS) = PT × RT =`1/2`(QT × RT)
= `8 xx RT = 1/2 ( 8 xx RT ) = 12 xx RT `
In , ΔQRT , we have
QR2 = QT2 + RT2
⇒ RT 2 = QR2 - QT2
⇒ ( RT )2 = 172 - 8 2 = 225
⇒ RT = 15
Hence, ar (trap . PQRS ) = 12 × 15cm 2 = 180 cm2
APPEARS IN
संबंधित प्रश्न
In fig below, ABCD is a parallelogram, AE ⊥ DC and CF ⊥ AD. If AB = 16 cm, AE = 8
cm and CF = 10 cm, find AD.

ABCD is a parallelogram whose diagonals intersect at O. If P is any point on BO, prove
that: (1) ar (ΔADO) = ar (ΔCDO) (2) ar (ΔABP) = ar (ΔCBP)
ABCD is a parallelogram. E is a point on BA such that BE = 2 EA and F is a point on DC
such that DF = 2 FC. Prove that AE CF is a parallelogram whose area is one third of the
area of parallelogram ABCD.
In the given figure, ABCD is a parallelogram. If AB = 12 cm, AE = 7.5 cm, CF = 15 cm, then AD =

In the given figure, ABCD and FECG are parallelograms equal in area. If ar (ΔAQE) = 12 cm2, then ar (||gm FGBQ) =

The perimeter of a triangle ABC is 37 cm and the ratio between the lengths of its altitudes be 6: 5: 4. Find the lengths of its sides.
Let the sides be x cm, y cm, and (37 - x - y) cm. Also, let the lengths of altitudes be 6a cm, 5a cm, and 4a cm.
What is the area of the rectangle? ________ square cm
Each line gives a story. You have to choose the question which makes the best story problem. The first one is already marked.
- 352 children from a school went on a camping trip. Each tent had a group of 4 children.
a) How many children did each tent have? b) How many tents do they need? c) How many children in all are in the school?
Find the area of the following figure by counting squares:

Find the area of the following figure by counting squares:

