Advertisements
Advertisements
प्रश्न
Find the area of a square, whose side is: 4.1 cm.
Advertisements
उत्तर
Area of the square = (side)²
= (4.1 cm)²
= 4.1 cm x 4.1 cm
= 16.81 cm²
APPEARS IN
संबंधित प्रश्न
If ABC and BDE are two equilateral triangles such that D is the mid-point of BC, then find ar (ΔABC) : ar (ΔBDE).
In the given figure, ABCD is a rectangle with sides AB = 10 cm and AD = 5 cm. Find the area of ΔEFG.

ABCD is a parallelogram. P is the mid-point of AB. BD and CP intersect at Q such that CQ: QP = 3.1. If ar (ΔPBQ) = 10cm2, find the area of parallelogram ABCD.
In a ΔABC, D, E, F are the mid-points of sides BC, CA and AB respectively. If ar (ΔABC) = 16cm2, then ar (trapezium FBCE) =
ABCD is a trapezium in which AB || DC. If ar (ΔABD) = 24 cm2 and AB = 8 cm, then height of ΔABC is
What will happen to the area of a rectangle, if its length and breadth both are trebled?
Area of a rectangle with length 5 cm and breadth 3 cm is ______.
The region given in the following figure is measured by taking
as a unit. What is the area of the region?

Find the area of the following figure by counting squares:

Which unit is used to express area?
