Advertisements
Advertisements
प्रश्न
Let ABCD be a parallelogram of area 124 cm2. If E and F are the mid-points of sides AB and
CD respectively, then find the area of parallelogram AEFD.
Advertisements
उत्तर

Given,
Area of parallelogram `ABCD = 124cm^2`
Construction: draw AP ⊥ DC
Proof :
Area of parallelogram AFED = DF × AP .......(1)
And area of parallelogram EBCF = FC × AP ......(2)
And DF = FC .............(3) [ F is the midpoint of DC ]
Compare equation (1), (2) and (3)
Area of parallelogram AEFD = Area of parallelogram EBCF
∴ Area of parallelogram ABCD = `" Area of parallelogram"/"2"`
` = 124 / 2 = 62cm^2`
APPEARS IN
संबंधित प्रश्न
In the below fig. X and Y are the mid-points of AC and AB respectively, QP || BC and
CYQ and BXP are straight lines. Prove that ar (Δ ABP) = ar (ΔACQ).

In square ABCD, P and Q are mid-point of AB and CD respectively. If AB = 8cm and PQand BD intersect at O, then find area of ΔOPB.
The area of the figure formed by joining the mid-points of the adjacent sides of a rhombus with diagonals 16 cm and 12 cm is
The side of a square is 3.6 cm; find its area.
Length of a rectangle is 30 m and its breadth is 20 m. Find the increase in its area if its length is increased by 10 m and its breadth is doubled.
In the same way, find the area of piece B.
Who had the bigger piece? How much bigger?
The amount of region enclosed by a plane closed figure is called its ______.
Area of a rectangle with length 5 cm and breadth 3 cm is ______.
If a figure contains only 8 fully-filled squares and no partial squares, what is its area?
