Advertisements
Advertisements
प्रश्न
In Q. No 1, if AD = 6 cm, CF = 10 cm, and AE = 8cm, find AB.
Advertisements
उत्तर

We know that,
Area of parallelogram ABCD = AD × CF ……(1)
Again area of parallelogram ABCD = DC × AE ……(2)
Compare equation (1) and equation (2)
AD × CF = DC × AE
⇒ 6 × 10 = D × B
⇒ ` D = 60 /8 = 7. 5cm`
∴ AB = DC = 7 . 5cm [ ∴ Opposite sides of a parallelogram are equal ]
APPEARS IN
संबंधित प्रश्न
Let ABCD be a parallelogram of area 124 cm2. If E and F are the mid-points of sides AB and
CD respectively, then find the area of parallelogram AEFD.
ABCD is a parallelogram. E is a point on BA such that BE = 2 EA and F is a point on DC
such that DF = 2 FC. Prove that AE CF is a parallelogram whose area is one third of the
area of parallelogram ABCD.
In below fig., PSDA is a parallelogram in which PQ = QR = RS and AP || BQ || CR. Prove
that ar (Δ PQE) = ar (ΔCFD).

If ABC and BDE are two equilateral triangles such that D is the mid-point of BC, then find ar (ΔABC) : ar (ΔBDE).
PQRS is a rectangle inscribed in a quadrant of a circle of radius 13 cm. A is any point on PQ. If PS = 5 cm, then find ar (ΔRAS)
ABCD is a parallelogram. P is the mid-point of AB. BD and CP intersect at Q such that CQ: QP = 3.1. If ar (ΔPBQ) = 10cm2, find the area of parallelogram ABCD.
The area of the figure formed by joining the mid-points of the adjacent sides of a rhombus with diagonals 16 cm and 12 cm is
Find the area of a rectangle whose length and breadth are 25 m and 16 cm.
In the same way, find the area of piece B.
Measure the length of the floor of your classroom in meters. Also, measure the width.
- What is the area of the floor of your classroom in square metres?
