Advertisements
Advertisements
प्रश्न
Find all the possible dimensions (in natural numbers) of a rectangle with a perimeter 36 cm and find their areas.
Advertisements
उत्तर
Perimeter of the rectangle = 36 cm
⇒ 2(Length + Breadth) = 36 cm
⇒ Length + Breadth = `36/2` cm = 18 cm
∴ The possible dimensions of the rectangle and their areas are as follows:
| Dimensions | Area |
| 1 cm × 17 cm | 17 cm2 |
| 2 cm × 16 cm | 32 cm2 |
| 3 cm × 15 cm | 45 cm2 |
| 4 cm × 14 cm | 56 cm2 |
| 5 cm × 13 cm | 65 cm2 |
| 6 cm × 12 cm | 72 cm2 |
| 7 cm × 11 cm | 77 cm2 |
| 8 cm × 10 cm | 80 cm2 |
| 9 cm × 9 cm | 81 cm2 |
APPEARS IN
संबंधित प्रश्न
In the below fig. ∠AOB = 90°, AC = BC, OA = 12 cm and OC = 6.5 cm. Find the area of
ΔAOB.
ABCD is a parallelogram whose diagonals intersect at O. If P is any point on BO, prove
that: (1) ar (ΔADO) = ar (ΔCDO) (2) ar (ΔABP) = ar (ΔCBP)
PQRS is a trapezium having PS and QR as parallel sides. A is any point on PQ and B is a point on SR such that AB || QR. If area of ΔPBQ is 17cm2, find the area of ΔASR.
The median of a triangle divides it into two ______.
In a ΔABC, D, E, F are the mid-points of sides BC, CA and AB respectively. If ar (ΔABC) = 16cm2, then ar (trapezium FBCE) =
Diagonal AC and BD of trapezium ABCD, in which AB || DC, intersect each other at O. The triangle which is equal in area of ΔAOD is
Cheggu’s wife asked him to make a circle with the wire. She knew it had an area of 800 square meters.
- Why did Cheggu not choose a rectangle? Explain.
The region given in the following figure is measured by taking 
as a unit. What is the area of the region?
Find the area of the following figure by counting squares:
Which unit is used to express area?
