Advertisements
Advertisements
प्रश्न
Find all the possible dimensions (in natural numbers) of a rectangle with a perimeter 36 cm and find their areas.
Advertisements
उत्तर
Perimeter of the rectangle = 36 cm
⇒ 2(Length + Breadth) = 36 cm
⇒ Length + Breadth = `36/2` cm = 18 cm
∴ The possible dimensions of the rectangle and their areas are as follows:
| Dimensions | Area |
| 1 cm × 17 cm | 17 cm2 |
| 2 cm × 16 cm | 32 cm2 |
| 3 cm × 15 cm | 45 cm2 |
| 4 cm × 14 cm | 56 cm2 |
| 5 cm × 13 cm | 65 cm2 |
| 6 cm × 12 cm | 72 cm2 |
| 7 cm × 11 cm | 77 cm2 |
| 8 cm × 10 cm | 80 cm2 |
| 9 cm × 9 cm | 81 cm2 |
APPEARS IN
संबंधित प्रश्न
If ABC and BDE are two equilateral triangles such that D is the mid-point of BC, then find ar (ΔABC) : ar (ΔBDE).
ABCD is a parallelogram. P is the mid-point of AB. BD and CP intersect at Q such that CQ: QP = 3.1. If ar (ΔPBQ) = 10cm2, find the area of parallelogram ABCD.
In a ΔABC, D, E, F are the mid-points of sides BC, CA and AB respectively. If ar (ΔABC) = 16cm2, then ar (trapezium FBCE) =
In a ΔABC if D and E are mid-points of BC and AD respectively such that ar (ΔAEC) = 4cm2, then ar (ΔBEC) =
Diagonal AC and BD of trapezium ABCD, in which AB || DC, intersect each other at O. The triangle which is equal in area of ΔAOD is
Who had the bigger piece? How much bigger?
Whose footprint is larger - yours or your friend’s?
Find the area of the following figure by counting squares:

Find the area of the following figure by counting squares:

Find the area of the following figure by counting squares:

