Advertisements
Advertisements
प्रश्न
Find all the possible dimensions (in natural numbers) of a rectangle with an area of 36 sq cm, and find their perimeters.
Advertisements
उत्तर
The area of the rectangle = 36 sq cm
⇒ Length × Breadth = 36 sq cm
∴ The possible dimensions of the rectangle and their perimeters are as follows:
| Dimensions | Perimeter |
| 1 cm × 36 cm | 2(1 + 36) cm = 74 cm |
| 2 cm × 18 cm | 2(2 + 18) cm = 40 cm |
| 3 cm × 12 cm | 2(3 + 12) cm = 30 cm |
| 4 cm × 9 cm | 2(4 + 9) cm = 26 cm |
| 6 cm × 6 cm | 2(6 + 6) cm = 24 cm |
APPEARS IN
संबंधित प्रश्न
Find the perimeter of a rectangle with length = 24 cm and diagonal = 25 cm
If P = perimeter of a rectangle, l= its length and b = its breadth find b, if P = 88 cm and l = 24 cm
Find the side of the square whose perimeter is 5 m.
If a square of side 1 cm is cut out of the corner of a larger square with side 3 cm (see the figure), what will be the perimeter of the remaining shape?

What is its perimeter __________
Find the perimeter of the following figure:

Find the perimeter of the following shape:
An equilateral triangle of side 9 cm.
Find the perimeter of the following shape:
An isosceles triangle with equal sides of 8 cm each and the third side of 6 cm.
If you start at point S on a closed figure and move along all line segments to return to S, what distance have you covered?
A polygon with sides 100 m, 120 m, 90 m, 45 m, 60 m, and 80 m has a perimeter of:
