Advertisements
Advertisements
प्रश्न
In the given figure, ABCD is a parallelogram. If AB = 12 cm, AE = 7.5 cm, CF = 15 cm, then AD =
Advertisements
उत्तर
Given: (1) ABCD is a parallelogram.
(2) AB = 12 cm
(3) AE = 7.5 cm
(4) CF = 15cm
To find: AD
Calculation: We know that,
Area of a parallelogram = base × height
Area of a parallelogram ABCD = DC ×AE (with DC as base and AE as height) ……(1)
Area of a parallelogram ABCD = AD ×CF (with DC as base and AE as height) ……(2)
Since equation 1 and 2 both are Area of a parallelogram ABCD
`DC xx AE = AD xx CF`
`AD = (DC xx AE)/(CF)`
`AD = (AB xx AE)/(CF)` (AB = DC , opposite sides of parallelogram are eual )
`AD = (12 xx 7.5)/15`
AD = 6 cm
APPEARS IN
संबंधित प्रश्न
If P is any point in the interior of a parallelogram ABCD, then prove that area of the
triangle APB is less than half the area of parallelogram.
In below fig., PSDA is a parallelogram in which PQ = QR = RS and AP || BQ || CR. Prove
that ar (Δ PQE) = ar (ΔCFD).
In the below fig. X and Y are the mid-points of AC and AB respectively, QP || BC and
CYQ and BXP are straight lines. Prove that ar (Δ ABP) = ar (ΔACQ).
P is any point on base BC of ΔABC and D is the mid-point of BC. DE is drawn parallel toPA to meet AC at E. If ar (ΔABC) = 12 cm2, then find area of ΔEPC.
The side of a square field is 16 m. What will be increase in its area, if each of its sides is increased by 4 m?
Who had the bigger piece? How much bigger?
Look at the table. If you were to write the area of each of these which column would you choose? Make a (✓).
| Square cm |
Square meter |
Square km |
|
| Handkerchief | ✓ | ||
| Sari | |||
| Page of your book | |||
| School land | |||
| Total land of a city | |||
| Door of your classroom | |||
| Chair seat | |||
| Blackboard | |||
| Indian flag | |||
| Land over which a river flows |
Find the area of the following figure by counting squares:
Find the area of the following figure by counting squares:
Find the area of the following figure by counting squares:
