Advertisements
Advertisements
प्रश्न
A point D is taken on the side BC of a ΔABC such that BD = 2DC. Prove that ar(Δ ABD) =
2ar (ΔADC).
Advertisements
उत्तर

GIven that ,
In ΔABC, BD = 2 DC
To prove: ar ( ΔABD ) = 2ar (ΔADC)
Construction: Take a point E on BD such that BE = ED
Proof : Since, BE = ED and 2 BD = 2DC
Then, BE = ED = DC
We know that median of Δledivides it into two equal Δles
∴ In , ΔABD , AE is a median
Then, area (ΔABD) 2ar (ΔAED) .....(1)
In , ΔAEC , AD is a median
Then area (ΔAED) = area (ΔADC) ...... (2)
Compare equation (1) and (2)
Area (ΔABD) = 2ar (ΔADC).
APPEARS IN
संबंधित प्रश्न
In Q. No 1, if AD = 6 cm, CF = 10 cm, and AE = 8cm, find AB.
In the given figure, ABCD is a parallelogram. If AB = 12 cm, AE = 7.5 cm, CF = 15 cm, then AD =

The perimeter of a triangle ABC is 37 cm and the ratio between the lengths of its altitudes be 6: 5: 4. Find the lengths of its sides.
Let the sides be x cm, y cm, and (37 - x - y) cm. Also, let the lengths of altitudes be 6a cm, 5a cm, and 4a cm.
Each side of a square is 7 m. If its each side be increased by 3 m, what will be the increase in its area.
Length of a rectangle is 30 m and its breadth is 20 m. Find the increase in its area if its length is increased by 10 m and its breadth is doubled.
Find the area and perimeter of the following parallelograms
The table given below contains some measures of the rectangle. Find the unknown values.
| Length | Breadth | Perimeter | Area |
| 13 cm | ? | 54 cm | ? |
The table given below contains some measures of the rectangle. Find the unknown values.
| Length | Breadth | Perimeter | Area |
| ? | 15 cm | 60 cm | ? |
Measure the length of the floor of your classroom in meters. Also, measure the width.
- So how many children can sit in one square meter?
Find the area of the following figure by counting squares:

