Advertisements
Advertisements
प्रश्न
The table given below contains some measures of the rectangle. Find the unknown values.
| Length | Breadth | Perimeter | Area |
| 13 cm | ? | 54 cm | ? |
Advertisements
उत्तर
l = 13 cm
p = 54 cm
Perimeter = 2(l + b) units
54 = 2(13 + b) cm
`54/2` = 13 + b
27 = 13 + b
b = 27 – 13
b = 14 cm
Area = l × b sq.unit
= 13 × 14 cm2
A = 182 cm2
Completing the unknown values in the table.
| Length | Breadth | Perimeter | Area |
| 13 cm | 14 cm | 54 cm | 182 cm2 |
APPEARS IN
संबंधित प्रश्न
In the below fig. ∠AOB = 90°, AC = BC, OA = 12 cm and OC = 6.5 cm. Find the area of
ΔAOB.

ABC is a triangle in which D is the mid-point of BC. E and F are mid-points of DC and AErespectively. IF area of ΔABC is 16 cm2, find the area of ΔDEF.
In the given figure, PQRS is a parallelogram. If X and Y are mid-points of PQ and SRrespectively and diagonal Q is joined. The ratio ar (||gm XQRY) : ar (ΔQSR) =

The length and breadth of a rectangular piece of land are in the ratio 5 : 3. If the total cost of fencing it at the rate of ₹24 per meter is ₹9600, find its :
(i) length and breadth
(ii) area
(iii) cost of levelling at the rate of ₹60 per m2.
Find the area of a rectangle whose length = 15 cm breadth = 6.4 cm
Altogether how many squares can be arranged on it?
Is the area of your belt the same as the area of the postcard? Why or why not?
A magazine charges Rs 300 per 10 sq cm area for advertising. A company decided to order a half page advertisment. If each page of the magazine is 15 cm × 24 cm, what amount will the company has to pay for it?
Find the area of the following figure by counting squares:

Find the area of the following figure by counting squares:

