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प्रश्न
The mid-points of the sides of a triangle ABC along with any of the vertices as the fourth point make a parallelogram of area equal to ______.
पर्याय
`1/2` ar (ABC)
- `1/3` ar (ABC)
- `1/4` ar (ABC)
- ar (ABC)
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उत्तर
The mid-points of the sides of a triangle ABC along with any of the vertices as the fourth point make a parallelogram of area equal to `underlinebb(1/2 ar (ABC))`.
Explanation:
Given: ABCD is a triangle.
Mid points of the sides of ΔABC with any of the vertices forms a parallelogram.
To find: Area of the parallelogram
Calculation: We know that, Area of a parallelogram = base × height

Hence area of || gm DECF = EC × EG
area of || gm DECF = EC × EG
area of || gm DECF = `1/2 BC xx 1/2 AE` ...(E is the midpoint of BC)
area of || gm DECF = `1/2(1/2BC xx AE)`
area of || gm DECF = `1/2(ar ( ΔABC) `
संबंधित प्रश्न
Let ABCD be a parallelogram of area 124 cm2. If E and F are the mid-points of sides AB and
CD respectively, then find the area of parallelogram AEFD.
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that: (1) ar (ΔADO) = ar (ΔCDO) (2) ar (ΔABP) = ar (ΔCBP)
ABCD is a parallelogram. E is a point on BA such that BE = 2 EA and F is a point on DC
such that DF = 2 FC. Prove that AE CF is a parallelogram whose area is one third of the
area of parallelogram ABCD.
In below fig., PSDA is a parallelogram in which PQ = QR = RS and AP || BQ || CR. Prove
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