Advertisements
Advertisements
प्रश्न
Medians of ΔABC intersect at G. If ar (ΔABC) = 27 cm2, then ar (ΔBGC) =
विकल्प
6 cm2
9 cm2
12 cm2
18 cm2
Advertisements
उत्तर
Given: (1) Median of ΔABC meet at G.
(2) Area of ΔABC = 27 cm2
To find: Area of ΔBCG.
We know that the medians of the triangle divides each other in the ratio of 2:1

Hence,
ar (ΔBED) = `1/2 xx BC xx GD`
ar (ΔBED) =`1/2 xx BC xx 1/3 (AD)`
ar (ΔBED) =`1/3(1/2xx AD xx BC)`
ar (ΔBED) =`1/3 (Δ ABC)`
ar (ΔBED) = = `1/3(27)`
ar (ΔBED) == 9 cm2
APPEARS IN
संबंधित प्रश्न
ABCD is a parallelogram. E is a point on BA such that BE = 2 EA and F is a point on DC
such that DF = 2 FC. Prove that AE CF is a parallelogram whose area is one third of the
area of parallelogram ABCD.
In the given figure, ABCD is a parallelogram. If AB = 12 cm, AE = 7.5 cm, CF = 15 cm, then AD =

ABCD is a trapezium with parallel sides AB =a and DC = b. If E and F are mid-points of non-parallel sides AD and BC respectively, then the ratio of areas of quadrilaterals ABFEand EFCD is
ABCD is a rectangle with O as any point in its interior. If ar (ΔAOD) = 3 cm2 and ar (ΔABOC) = 6 cm2, then area of rectangle ABCD is
Find the area of a rectangle whose length = 8.5 m breadth = 5 m.
Each side of a square is 7 m. If its each side be increased by 3 m, what will be the increase in its area.
By counting squares, estimate the area of the figure.

Altogether how many squares can be arranged on it?
Measure the length of the floor of your classroom in meters. Also, measure the width.
- What is the area of the floor of your classroom in square metres?
An engineer who plans to build a compound wall on all sides of a house must find the area of the compound.
