Advertisements
Advertisements
प्रश्न
In a ΔABC if D and E are mid-points of BC and AD respectively such that ar (ΔAEC) = 4cm2, then ar (ΔBEC) =
विकल्प
4 cm2
6 cm2
8 cm2
12 cm2
Advertisements
उत्तर
Given: In ΔABC
(1) D is the midpoint of BC
(2) E is the midpoint of AD
(3) ar (ΔAEC) = 4 cm2
To find: ar (ΔBEC)
Calculation: We know that”the median of the triangle divides the triangle into two triangle of equal area”

Since AD is the median of ΔABC,
ar (ΔABD) = ar (ΔADC) …… (1)
EC is the median of ΔADC,
ar (ΔAEC) = ar (ΔDEC) …… (2)
⇒ ar (ΔDEC) = 4 cm2
EC is the median of ΔBED
ar (ΔBED) = ar (ΔDEC) …… (3)
From 2 and 3 we get,
ar (ΔBED) = ar (ΔAEC) …… (4)
⇒ ar (ΔBED) = 4 cm2
Now,
ar (ΔBEC) = ar (ΔBED) + ar (ΔDEC)
= 4 + 4 (subsituting the values)
ar(ΔBEC) = 8 cm2
APPEARS IN
संबंधित प्रश्न
Compute the area of trapezium PQRS is Fig. below.

PQRS is a rectangle inscribed in a quadrant of a circle of radius 13 cm. A is any point on PQ. If PS = 5 cm, then find ar (ΔRAS)
In square ABCD, P and Q are mid-point of AB and CD respectively. If AB = 8cm and PQand BD intersect at O, then find area of ΔOPB.
ABCD is a trapezium with parallel sides AB =a and DC = b. If E and F are mid-points of non-parallel sides AD and BC respectively, then the ratio of areas of quadrilaterals ABFEand EFCD is
The medians of a triangle ABC intersect each other at point G. If one of its medians is AD,
prove that:
(i) Area ( ΔABD ) = 3 x Area ( ΔBGD )
(ii) Area ( ΔACD ) = 3 x Area ( ΔCGD )
(iii) Area ( ΔBGC ) = `1/3` x Area ( ΔABC ).
The length and breadth of a rectangular piece of land are in the ratio 5 : 3. If the total cost of fencing it at the rate of ₹24 per meter is ₹9600, find its :
(i) length and breadth
(ii) area
(iii) cost of levelling at the rate of ₹60 per m2.
The King was very happy with carpenters Cheggu and Anar. They had made a very big and beautiful bed for him. So as gifts the king wanted to give some land to Cheggu, and some gold to Anar. Cheggu was happy. He took 100 meters of wire and tried to make different rectangles.
He made a 10 m × 40 m rectangle. Its area was 400 square meters. So he next made a 30 m × 20 m rectangle.
- What other rectangles can he make with 100 meters of wire? Discuss which of these rectangles will have the biggest area.
Each line gives a story. You have to choose the question which makes the best story problem. The first one is already marked.
- A shopkeeper has 50 boxes. There are 48 fruits in one box.
Tick the one question which matches with the given problem.
Explain why (a) and (c) are not good choices.a) How much will the shopkeeper pay in all? b) How many fruits are there in all? ✓ c) How many more boxes will he need?
In the following figure, the area of parallelogram ABCD is ______.

Find the area of the following figure by counting squares:

