X, ∀X ∈ R .Then Find Fog and Gof. Hence Find Fog(–3), Fog(5) and Gof (–2). | Shaalaa.com" /> X, ∀X ∈ R .Then Find Fog and Gof. Hence Find Fog(–3), Fog(5) and Gof (–2). " /> X, ∀X ∈ R .Then Find Fog and Gof. Hence Find Fog(–3), Fog(5) and Gof (–2)., Types of Functions" />
हिंदी

If F, G : R → R Be Two Functions Defined As F(X) = |X| + X And G(X) = |X| X, ∀X∈R" > X, ∀X ∈ R .Then Find Fog and Gof. Hence Find Fog(–3), Fog(5) and Gof (–2).

Advertisements
Advertisements

प्रश्न

 If f, g : R → R be two functions defined as f(x) = |x| + x and g(x) = |x|- x, ∀x∈R" .Then find fog and gof. Hence find fog(–3), fog(5) and gof (–2).

योग
Advertisements

उत्तर

Given: f(x) = |x| + x 
and g(x) = |x| -x, ∀x ∈ R

fog = f(g(x)) = | g (x) | + g(x)

                    = ||x| − x|+(|x| − x)

Therefore,

f( g(x)) = `{ (0               x ≥ 0), (4x              x <0):}`

f( g(x)) = `{ (4x               x > 0), (0            x ≥ 0):}`

gof =  g (f(x)) = |f(x)| − f (x)

                      = ||x|+x| − (|x|+x)

g(f(x)) = `{(0              x ≥ 0), (0             x < 0):}`

Therefore, g (f(x)) = gof = 0

Now, fog(−3) =(4)(−3) = −12                                (since, fog = 4x for x < 0)

fog (5) = 0                                                              (since, fog = 0 for x ≥ 0)

 gof(−2) = 0                                                           (since, gof = 0 for x < 0)

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Functions - Exercise 2.3 [पृष्ठ ५५]

APPEARS IN

आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 2 Functions
Exercise 2.3 | Q 13 | पृष्ठ ५५

वीडियो ट्यूटोरियलVIEW ALL [5]

संबंधित प्रश्न

Show that the function f in `A=R-{2/3} ` defined as `f(x)=(4x+3)/(6x-4)` is one-one and onto hence find f-1


Check the injectivity and surjectivity of the following function:

f : N → N given by f(x) = x2


Check the injectivity and surjectivity of the following function:

f : R → R given by f(x) = x2


Check the injectivity and surjectivity of the following function:

f : N → N given by f(x) = x3


Let A = {1, 2, 3}, B = {4, 5, 6, 7} and let f = {(1, 4), (2, 5), (3, 6)} be a function from A to B. Show that f is one-one.


Let A = R – {3} and B = R – {1}. Consider the function f : A → B defined by f(x) = `((x - 2)/(x - 3))`. Is f one-one and onto? Justify your answer.


Given examples of two functions fN → N and gN → N such that gof is onto but is not onto.

(Hint: Consider f(x) = x + 1 and `g(x) = {(x-1, ifx >1),(1, if x = 1):}`


Classify the following function as injection, surjection or bijection :

f : R → R, defined by f(x) = |x|


Classify the following function as injection, surjection or bijection :

f : Q → Q, defined by f(x) = x3 + 1


Classify the following function as injection, surjection or bijection :

f : R → R, defined by f(x) = 3 − 4x


If f : A → B is an injection, such that range of f = {a}, determine the number of elements in A.


Let A = [-1, 1]. Then, discuss whether the following functions from A to itself is one-one, onto or bijective : h(x) = x2 


Let A = {abc}, B = {u vw} and let f and g be two functions from A to B and from B to A, respectively, defined as :
f = {(av), (bu), (cw)}, g = {(ub), (va), (wc)}.
Show that f and g both are bijections and find fog and gof.


 Find fog and gof  if  : f (x) = ex g(x) = loge x .


Let f(x) = x2 + x + 1 and g(x) = sin x. Show that fog ≠ gof.


if f (x) = `sqrt (x +3) and  g (x) = x ^2 + 1` be two real functions, then find fog and gof.


Let

f (x) =`{ (1 + x, 0≤ x ≤ 2) , (3 -x , 2 < x ≤ 3):}`

Find fof.


Consider the function f : R→  [-9 , ∞ ]given by f(x) = 5x2 + 6x - 9. Prove that f is invertible with -1 (y) = `(sqrt(54 + 5y) -3)/5`             [CBSE 2015]


If A = {1, 2, 3, 4} and B = {abcd}, define any four bijections from A to B. Also give their inverse functions.


If f(x) = x + 7 and g(x) = x − 7, x ∈ R, write fog (7).


Let the function

\[f : R - \left\{ - b \right\} \to R - \left\{ 1 \right\}\]

\[f\left( x \right) = \frac{x + a}{x + b}, a \neq b .\text{Then},\]

 


If a function\[f : [2, \infty )\text{ to B defined by f}\left( x \right) = x^2 - 4x + 5\] is a bijection, then B =


Let

\[f : R - \left\{ n \right\} \to R\]

\[f\left( x \right) = \frac{x - m}{x - n}, \text{where} \ m \neq n .\] Then,
 

\[f : Z \to Z\]  be given by

 ` f (x) = {(x/2, ", if  x is even" ) ,(0 , ", if  x  is  odd "):}`

Then,  f is


If  \[f : R \to \left( - 1, 1 \right)\] is defined by

\[f\left( x \right) = \frac{- x|x|}{1 + x^2}, \text{ then } f^{- 1} \left( x \right)\] equals

 


Let A = ℝ − {3}, B = ℝ − {1}. Let f : A → B be defined by \[f\left( x \right) = \frac{x - 2}{x - 3}, \forall x \in A\] Show that f is bijective. Also, find
(i) x, if f−1(x) = 4
(ii) f−1(7)


Are the following set of ordered pairs functions? If so, examine whether the mapping is injective or surjective.
{(a, b): a is a person, b is an ancestor of a}


Let X = {1, 2, 3}and Y = {4, 5}. Find whether the following subset of X ×Y are function from X to Y or not

h = {(1,4), (2, 5), (3, 5)}


Let A = [–1, 1]. Then, discuss whether the following functions defined on A are one-one, onto or bijective:

f(x) = `x/2`


Let A = [–1, 1]. Then, discuss whether the following functions defined on A are one-one, onto or bijective:

g(x) = |x|


The smallest integer function f(x) = [x] is ____________.


Let f : R → R be a function defined by f(x) `= ("e"^abs"x" - "e"^-"x")/("e"^"x" + "e"^-"x")` then f(x) is


If f: R → R given by f(x) =(3 − x3)1/3, find f0f(x)


If f: R→R is a function defined by f(x) = `[x - 1]cos((2x - 1)/2)π`, where [ ] denotes the greatest integer function, then f is ______.


Difference between the greatest and least value of f(x) = `(1 + (cos^-1x)/π)^2 - (1 + (sin^-1x)/π)^2` is ______.


A function is onto when every element of the codomain has:


If every seat in a classroom is occupied by one student, the situation resembles:


Which condition represents an onto (surjective) function?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×