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From the rate expression for the following reaction, determine the order of reaction and the dimension of the rate constant. CH3⁢CHO(g) -> CH4⁢(g) + CO(g) Rate = k [CH3CHO]3/2

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प्रश्न

From the rate expression for the following reaction, determine the order of reaction and the dimension of the rate constant.

\[\ce{CH3CHO_{(g)} -> CH4_{(g)} + CO_{(g)}}\] Rate = k [CH3CHO]3/2

संख्यात्मक
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उत्तर

Given rate = k [CH3CHO]3/2

∴ Order of reaction = \[\ce{\frac{3}{2}}\]

Dimension of k = \[\ce{\frac{Rate}{[CH3CHO]^{3/2}}}\]

= \[\ce{\frac{(mol L^{-1} s^{-1})}{(mol L^{-1})^{3/2}}}\]

= L1/2 mol−1/2 s−1

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अध्याय 3: Chemical Kinetics - Exercises [पृष्ठ ८५]

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