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Question
From the rate expression for the following reaction, determine the order of reaction and the dimension of the rate constant.
\[\ce{CH3CHO_{(g)} -> CH4_{(g)} + CO_{(g)}}\] Rate = k[CH3CHO]3/2
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Solution
Given rate = k[CH3CHO]3/2
∴ Order of reaction = \[\ce{\frac{3}{2}}\]
Dimension of k = \[\ce{\frac{Rate}{[CH3CHO]^{3/2}}}\]
= \[\ce{\frac{(mol L^{-1} s^{-1})}{(mol L^{-1})^{3/2}}}\]
= L1/2 mol−1/2 s−1
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