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For the first order thermal decomposition reaction, the following data were obtained

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प्रश्न

For the first order thermal decomposition reaction, the following data were obtained:

Time / sec               Totalpressure / atm

0                              0.30

300                          0.50

Calculate the rate constant

(Given: log 2 = 0.301, log3 = 0.4771, log 4 = 0.6021)

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उत्तर

Given :

Pi = 0.30 atm

Pt = 0.50 atm

C2H5Cl(g)→C2H4(g)+HCl(g)

  Pi    0    0    (At t = 0 sec)

Pi-x   x    x     (At t = 300 sec)

So,

Pi - x + x + x = Pt

0.3+x = 0.5

x = 0.2

Then, Pi - x = 0.3 - 0.2 = 0.1 atm

For first order reaction,

`k=2.303/tlog(P_i/(P_i-x))`

`=2.303/tlog(0.3/0.1)`

`=(2.303xxlog3)/300=(2.303xx0.4771)/300`

 k = 0.0037 s-1

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2015-2016 (March) All India Set 2 C

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