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प्रश्न
Complete the Following table.
| Sr. no. | Type of Satellite | The names of Indian Satellite and launcher |
| (1) | Navigational Satellite | Satellite: ______ |
| Launcher: ______ | ||
| (2) | Earth Observation Satellite | Satellite: ______ |
| Launcher: ______ |
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उत्तर
| Sr. no. | Type of Satellite | The names of Indian Satellite and launcher |
| (1) | Navigational Satellite | Satellite: IRNSS |
| Launcher: PSLV | ||
| (2) | Earth Observation Satellite | Satellite: IRS |
| Launcher: PSLV |
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संबंधित प्रश्न
Fill in the blank and explain the statement with reasoning:
If the height of the orbit of a satellite from the earth surface is increased, the tangential velocity of the satellite will ......
Answer the question:
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Why are geostationary satellites not useful for studies of polar regions?
Solve the problem.
How much time a satellite in an orbit at height 35780 km above earth's surface would take, if the mass of the earth would have been four times its original mass?
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Write the proper name of the orbits of satellites shown in the following figure with their height from the earth’s surface.

Calculate the critical velocity of the satellite to be located at 35780 km above the surface of earth.
Distinguish between:
High Earth orbit - Medium Earth orbit.
How is a satellite maintained in nearly circular orbit?
Why are some satellites called geostationary?
Numerical problem.
At an orbital height of 400 km, find the orbital period of the satellite.
Give scientific reasons.
The geostationary satellite is not useful in the study of polar regions.
Calculate the time taken by a satellite for one revolution revolving at a height of 6400 km above the earth's surface with a velocity of 5.6 km/s.
The height of medium earth orbit above the surface of the earth is ______.
Complete the following equations:

The orbit of a satellite is exactly 35780 km above the earth's surface and its tangential velocity is 3.08 km/s.
How much time the satellite will take to complete one revolution around the earth?
(Radius of earth = 6400 km.)
