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प्रश्न
Note the relationship between the entries in all the three columns in the table and rewrite the table.
| Column-1 (Location) |
Column-2 Height from the earth’s surface (km) |
Column-3 g (m/s2) |
| Earth’s surface (average) | 8.8 | 0.225 |
| Mount Everest | 36.6 | 9.81 |
| The highest height ever reached by man made balloon | 400 | 9.8 |
| Orbit of spacecraft | 35700 | 9.77 |
| Orbit of communication satellite | 0 | 8.7 |
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उत्तर
| Column-1 (Location) |
Column-2 Height from the earth’s surface (km) |
Column-3 g (m/s2) |
| Earth’s surface (average) | 0 | 9.81 |
| Mount Everest | 8.8 | 9.8 |
| The highest height ever reached by man made balloon | 36.6 | 9.77 |
| Orbit of spacecraft | 400 | 8.7 |
| Orbit of communication satellite | 35700 | 0.225 |
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संबंधित प्रश्न
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Numerical problem.
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Calculate the time taken by a satellite for one revolution revolving at a height of 6400 km above the earth's surface with a velocity of 5.6 km/s.
Write the name of small satellite made by a group of students from COEP (College of Engineering, Pune) sent to the space through ISRO in 2016.
Complete the following equations:
The orbit of a satellite is exactly 35780 km above the earth's surface and its tangential velocity is 3.08 km/s.
How much time the satellite will take to complete one revolution around the earth?
(Radius of earth = 6400 km.)
