Advertisements
Advertisements
प्रश्न
Write the proper name of the orbits of satellites shown in the following figure with their height from the earth’s surface.

Advertisements
उत्तर
a) low earth orbits height above the earth’s surface: 180 km to 2000 km
b) Medium earth orbits height above the earth’s surface: 2000 km to 35780 km 12
c) high earth orbits 12 height from the earth’s surface > 35780 km
APPEARS IN
संबंधित प्रश्न
Why are geostationary satellites not useful for studies of polar regions?
Complete the following table.

Solve the problem.
How much time a satellite in an orbit at height 35780 km above earth's surface would take, if the mass of the earth would have been four times its original mass?
If the height of a satellite completing one revolution around the earth in T seconds is h1 meter, then what would be the height of a satellite taking \[2\sqrt{2} T\] seconds for one revolution?
Considering first correlation, complete the second.
Hubble telescope : At 569 km above the earth’s surface
Orbit of Hubble telescope : .............................
A group of students from COEP Pune sent a small satellite _______ through ISRO in 2016.
The function of a satellite launcher is based on Newton's second law of motion.
What is Medium Earth Orbit?
Distinguish between:
High Earth orbit - Medium Earth orbit.
Observe the figure and write the answers.

- Name the outer orbit.
- Which satellites revolve in low earth orbits?
- Which various orbits are given in the figure?
- Give an example of a launch vehicle based on Newton’s third law.
Note the relationship between the entries in all the three columns in the table and rewrite the table.
| Column-1 (Location) |
Column-2 Height from the earth’s surface (km) |
Column-3 g (m/s2) |
| Earth’s surface (average) | 8.8 | 0.225 |
| Mount Everest | 36.6 | 9.81 |
| The highest height ever reached by man made balloon | 400 | 9.8 |
| Orbit of spacecraft | 35700 | 9.77 |
| Orbit of communication satellite | 0 | 8.7 |
Numerical problem.
Calculate the speed with which a satellite moves if it is at a height of 36,000 km from the Earth’s surface and has an orbital period of 24 hr (Take R = 6370 km) [Hint: Convert hr into seconds before doing calculation]
Numerical problem.
At an orbital height of 400 km, find the orbital period of the satellite.
What is microgravity?
Give scientific reasons.
The geostationary satellite is not useful in the study of polar regions.
