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प्रश्न
The height of medium earth orbit above the surface of the earth is ______.
विकल्प
1,500 km
250 km
45,000 km
25,000 km
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उत्तर
The height of medium earth orbit above the surface of the earth is 25,000 km.
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संबंधित प्रश्न
Fill in the blank and explain the statement with reasoning:
If the height of the orbit of a satellite from the earth surface is increased, the tangential velocity of the satellite will ......
Solve the problem.
How much time a satellite in an orbit at height 35780 km above earth's surface would take, if the mass of the earth would have been four times its original mass?
Mahendra and Virat are sitting at a distance of 1 metre from each other. Their masses are 75 kg and 80 kg respectively. What is the gravitational force between them? G = 6.67 x 10-11 Nm2/kg2
Write the proper name of the orbits of satellites shown in the following figure with their height from the earth’s surface.
Calculate the critical velocity of the satellite to be located at 35780 km above the surface of earth.
Distinguish between:
High Earth orbit - Medium Earth orbit.
Observe the figure and write the answers.
- Name the outer orbit.
- Which satellites revolve in low earth orbits?
- Which various orbits are given in the figure?
- Give an example of a launch vehicle based on Newton’s third law.
Define orbital velocity.
Why are some satellites called geostationary?
Numerical problem.
Calculate the speed with which a satellite moves if it is at a height of 36,000 km from the Earth’s surface and has an orbital period of 24 hr (Take R = 6370 km) [Hint: Convert hr into seconds before doing calculation]
Numerical problem.
At an orbital height of 400 km, find the orbital period of the satellite.
What is microgravity?
The orbital velocity of the satellite depends on its ______.
Give scientific reasons.
The geostationary satellite is not useful in the study of polar regions.
Geostationary satellites are not useful for studies of the polar region.
Calculate the time taken by a satellite for one revolution revolving at a height of 6400 km above the earth's surface with a velocity of 5.6 km/s.
The orbit of a satellite is exactly 35780 km above the earth's surface and its tangential velocity is 3.08 km/s.
How much time the satellite will take to complete one revolution around the earth?
(Radius of earth = 6400 km.)
