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Account for the following observations: PbO2 is a stronger oxidising agent than SnO2

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प्रश्न

Account for the following observations:

PbO2 is a stronger oxidising agent than SnO2 

दीर्घउत्तर
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उत्तर

PbO2, lead is in +2 oxidation state and can be reduced to its most stable oxidation state of +2. Hence PbO2 can be further exidised or act as a strong oxidising agent. and in SnO, Sn is and +2 oxidation state and can extend its oxidation state up to +4. Thus, SnO can be used as a reducing agent.

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अध्याय 11: The p-block Elements - Multiple Choice Questions (Type - I) [पृष्ठ १४१]

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एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 11
अध्याय 11 The p-block Elements
Multiple Choice Questions (Type - I) | Q 42.(iii) | पृष्ठ १४१

संबंधित प्रश्न

If B–Cl bond has a dipole moment, explain why BCl3 molecule has zero dipole moment.


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Explain why the following compounds behave as Lewis acids?

AlCl3


Explain the following:

PbX2 is more stable than PbX4.


Explain the following:

Electron gain enthalpy of chlorine is more negative as compared to fluorine.


Identify the compounds A, X and Z in the following reactions:

\[\ce{A + 2HCl + 5H2O -> 2NaCl + X}\]


Match the species given in Column I with the properties mentioned in Column II.

Column I Column II
(i) \[\ce{BF^{-}4}\] (a) Oxidation state of central atom is +4
(ii) AICI3 (b) Strong oxidising agent
(iii) SnO (c) Lewis acid
(iv) PbO2 (d) Can be further oxidised
  (e) Tetrahedral shape

Match the species given in Column I with the hybridisation given in Column II.

Column I Column II
(i) Boron in [B(OH)4]– (a) sp2
(ii) Aluminium in [Al(H2O)6]3+ (b) sp3
(iii) Boron in B2H6 (c) sp3d2
(iv) Carbon in Buckminsterfullerene  
(v) Silicon in \[\ce{SiO^{4-}4}\]  
(vi) Germanium in [GeCl6]2–  

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Ionisation enthalpy


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Which one of the following is the correct statement?


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