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The geometry of a complex species can be understood from the knowledge of type of hybridisation of orbitals of central atom. The hybridisation of orbitals of central atom in [Be(OH)4]

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प्रश्न

The geometry of a complex species can be understood from the knowledge of type of hybridisation of orbitals of central atom. The hybridisation of orbitals of central atom in [Be(OH)4] and the geometry of the complex are respectively.

विकल्प

  • sp3, tetrahedral

  • sp3, square planar

  • sp3d2, octahedral

  • dsp2, square planar

MCQ
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उत्तर

sp3, tetrahedral

Explanation:

Boron has die electronic configuration: 1s2 2s2 2px1 2p0 y 2p0z

In the excited state, 2s-orbital electrons are impaired and one electron is shifted to a p-orbital. Now, hybridisation occurs between one s-and three p-orbitals to give sp3 hybridisation and tetrahedral geometry.

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अध्याय 11: The p-block Elements - Multiple Choice Questions (Type - I) [पृष्ठ १३४]

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एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 11
अध्याय 11 The p-block Elements
Multiple Choice Questions (Type - I) | Q 3 | पृष्ठ १३४

संबंधित प्रश्न

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Which of the following statements are correct. Answer on the basis of Figure.

(i) The two birdged hydrogen atoms and the two boron atoms lie in one plane;

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(iii) Out of six B – H bonds four B – H bonds can be described in terms of 3 centre 2 electron bonds;

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Boron does not exist as B3+ ion.


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PbX2 is more stable than PbX4.


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\[\ce{A + 2HCl + 5H2O -> 2NaCl + X}\]


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Though fluorine is more electronegative than chlorine yet BF3 is a weaker Lewis acid than BCl3 


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