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प्रश्न
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उत्तर
We know that,
P=VI
I = `"P"/"V" = (5 xx 1000)/200` = 25A
Thus, safe limit of current through t he appliance is 25A and a fuse of rating BA cannot be used with an appliance of rating SkW, 200 v.
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संबंधित प्रश्न
The circuit diagram given below shows the combination of three resistors R1, R2 and R3:
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(ii) total current flowing in the circuit.
(iii) the potential difference across R1.
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(a) Current which flows in the element when it is connected to a 250 V supply,
(b) Resistance of the filament,
(c) Heat produced in 1 minute by the element,
(d) Cost of running the kettle for 10 minutes a day for 30 days of the month, at the rate of Rs. 3.00 per unit.
Three heaters each rated 250 W, 100 V are connected in parallel to a 100 V supply of the energy supplied in kWh to the three heaters in 5 hours.
