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RD Sharma solutions for Mathematics [English] Class 12 chapter 29 - The Plane [Latest edition]

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RD Sharma solutions for Mathematics [English] Class 12 chapter 29 - The Plane - Shaalaa.com
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Solutions for Chapter 29: The Plane

Below listed, you can find solutions for Chapter 29 of CBSE, Karnataka Board PUC RD Sharma for Mathematics [English] Class 12.


Exercise 29.01Exercise 29.02Exercise 29.03Exercise 29.04Exercise 29.05Exercise 29.06Exercise 29.07Exercise 29.08Exercise 29.09Exercise 29.10Exercise 29.11Exercise 29.12Exercise 29.13Exercise 29.14Exercise 29.15Very Short AnswersMCQ
Exercise 29.01 [Pages 4 - 5]

RD Sharma solutions for Mathematics [English] Class 12 29 The Plane Exercise 29.01 [Pages 4 - 5]

1.1Page 4

Find the equation of the plane passing through the following points.

 (2, 1, 0), (3, −2, −2) and (3, 1, 7)

1.2Page 4

Find the equation of the plane passing through the following points.

 (−5, 0, −6), (−3, 10, −9) and (−2, 6, −6)

1.3Page 4

Find the equation of the plane passing through the following point

 (1, 1, 1), (1, −1, 2) and (−2, −2, 2)

1.4Page 4

Find the equation of the plane passing through the following points. 

(2, 3, 4), (−3, 5, 1) and (4, −1, 2) 

 

1.5Page 4

Find the equation of the plane passing through the following point

(0, −1, 0), (3, 3, 0) and (1, 1, 1)

 

 

2Page 5

Show that the four points (0, −1, −1), (4, 5, 1), (3, 9, 4) and (−4, 4, 4) are coplanar and find the equation of the common plane.

3.1Page 5

Show that the following points are coplanar.
 (0, −1, 0), (2, 1, −1), (1, 1, 1) and (3, 3, 0) 

3.2Page 5

Show that the following points are coplanar. 

 (0, 4, 3), (−1, −5, −3), (−2, −2, 1) and (1, 1, −1)

 
4Page 5

Find the coordinates of the point where the line through (3, -4 , -5 ) and B (2, -3 , 1) crosses the plane passing through three points L(2,2,1), M(3,0,1) and N(4, -1,0 ) . Also, find the ratio in which diveides the line segment AB.

Exercise 29.02 [Page 7]

RD Sharma solutions for Mathematics [English] Class 12 29 The Plane Exercise 29.02 [Page 7]

1Page 7

Write the equation of the plane whose intercepts on the coordinate axes are 2, −3 and 4.

 
2.1Page 7

Reduce the equations of the following planes to intercept form and find the intercepts on the coordinate axes.
4x + 3y − 6z − 12 = 0

2.2Page 7

Reduce the equations of the following planes to intercept form and find the intercepts on the coordinate axes. 

 2x + 3y − z = 6

2.3Page 7

Reduce the equations of the following planes to intercept form and find the intercepts on the coordinate axes. 

2x − y + z = 5

 

 

3Page 7

Find the equation of a plane which meets the axes at AB and C, given that the centroid of the triangle ABC is the point (α, β, γ). 

4Page 7

Find the equation of the plane passing through the point (2, 4, 6) and making equal intercepts on the coordinate axes.

5Page 7

A plane meets the coordinate axes at AB and C, respectively, such that the centroid of triangle ABC is (1, −2, 3). Find the equation of the plane.

Exercise 29.03 [Pages 13 - 14]

RD Sharma solutions for Mathematics [English] Class 12 29 The Plane Exercise 29.03 [Pages 13 - 14]

1Page 13

Find the vector equation of a plane passing through a point with position vector \[2 \hat{i} - \hat{j} + \hat{k} \] and perpendicular to the vector  \[4 \hat{i} + 2 \hat{j} - 3 \hat{k} .\] 

2.1Page 13

Find the Cartesian form of the equation of a plane whose vector equation is 

 \[\vec{r} \cdot \left( 12 \hat{i} - 3 \hat{j} + 4 \hat{k} \right) + 5 = 0\]

 

2.2Page 13

Find the Cartesian form of the equation of a plane whose vector equation is 

  \[\vec{r} \cdot \left( - \hat{i} + \hat{j}  + 2 \hat{k} \right) = 9\]

 

3Page 13

Find the vector equations of the coordinate planes.

 
4.1Page 13

Find the vector equation of each one of following planes. 

2x − y + 2z = 8

4.2Page 13

Find the vector equation of each one of following planes. 

x + y − z = 5

 

4.3Page 13

Find the vector equation of each one of following planes. 

x + y = 3

 
5Page 13

Find the vector and Cartesian equations of a plane passing through the point (1, −1, 1) and normal to the line joining the points (1, 2, 5) and (−1, 3, 1).

 
6Page 13

\[\vec{n}\] is a vector of magnitude \[\sqrt{3}\] and is equally inclined to an acute angle with the coordinate axes. Find the vector and Cartesian forms of the equation of a plane which passes through (2, 1, −1) and is normal to \[\vec{n}\] .

 

7Page 13

The coordinates of the foot of the perpendicular drawn from the origin to a plane are (12, −4, 3). Find the equation of the plane.

 
8Page 13

Find the equation of the plane passing through the point (2, 3, 1), given that the direction ratios of the normal to the plane are proportional to 5, 3, 2.

 
9Page 13

If the axes are rectangular and P is the point (2, 3, −1), find the equation of the plane through P at right angles to OP.

 
10Page 13

Find the intercepts made on the coordinate axes by the plane 2x + y − 2z = 3 and also find the direction cosines of the normal to the plane.

11Page 13

A plane passes through the point (1, −2, 5) and is perpendicular to the line joining the origin to the point

\[ \text{ 3 } \hat{i} + \hat{j} - \hat{k} .\] Find the vector and Cartesian forms of the equation of the plane.

 

12Page 13

Find the equation of the plane that bisects the line segment joining the points (1, 2, 3) and (3, 4, 5) and is at right angle to it.

 
13.1Page 13

Show that the normals to the following pairs of planes are perpendicular to each other. 

x − y + z − 2 = 0 and 3x + 2y − z + 4 = 0 

13.2Page 13

Show that the normals to the following pairs of planes are perpendicular to each other.

\[\vec{r} \cdot \left( 2 \hat{i}  - \hat{j}  + 3 \hat{k}  \right) = 5 \text{ and }  \vec{r} \cdot \left( 2 \hat{i}  - 2 \hat{j}  - 2 \hat{k}  \right) = 5\]
14Page 13

Show that the normal vector to the plane 2x + 2y + 2z = 3 is equally inclined to the coordinate axes.

 
15Page 14

Find a vector of magnitude 26 units normal to the plane 12x − 3y + 4z = 1.

16Page 14

If the line drawn from (4, −1, 2) meets a plane at right angles at the point (−10, 5, 4), find the equation of the plane.

17Page 14

Find the equation of the plane which bisects the line segment joining the points (−1, 2, 3) and (3, −5, 6) at right angles.

18Page 14

Find the vector and Cartesian equations of the plane that passes through the point (5, 2, −4) and is perpendicular to the line with direction ratios 2, 3, −1.

19Page 14

If O be the origin and the coordinates of P be (1, 2,−3), then find the equation of the plane passing through P and perpendicular to OP.

20Page 14

Find the vector equation of the plane with intercepts 3, –4 and 2 on x, y and z-axis respectively.

21Page 14

Find the vector equation of the plane with intercepts 3, –4 and 2 on x, y and z-axis respectively.

Exercise 29.04 [Page 19]

RD Sharma solutions for Mathematics [English] Class 12 29 The Plane Exercise 29.04 [Page 19]

1Page 19

Find the vector equation of a plane which is at a distance of 3 units from the origin and has \[\hat{k}\] as the unit vector normal to it.

2Page 19

Find the vector equation of a plane which is at a distance of 5 units from the origin and which is normal to the vector  \[\hat{i}  - \text{2 } \hat{j}  -  \text{2 } \hat{k} .\]

 

3Page 19

Reduce the equation 2x − 3y − 6z = 14 to the normal form and, hence, find the length of the perpendicular from the origin to the plane. Also, find the direction cosines of the normal to the plane. 

4Page 19

Reduce the equation \[\vec{r} \cdot \left( \hat{i}  - 2 \hat{j}  + 2 \hat{k}  \right) + 6 = 0\] to normal form and, hence, find the length of the perpendicular from the origin to the plane.

 

5Page 19

Write the normal form of the equation of the plane 2x − 3y + 6z + 14 = 0.

 
6Page 19

The direction ratios of the perpendicular from the origin to a plane are 12, −3, 4 and the length of the perpendicular is 5. Find the equation of the plane. 

7Page 19

Find a unit normal vector to the plane x + 2y + 3z − 6 = 0.

 
8Page 19

Find the equation of a plane which is at a distance of \[3\sqrt{3}\]  units from the origin and the normal to which is equally inclined to the coordinate axes.

 
9Page 19

find the equation of the plane passing through the point (1, 2, 1) and perpendicular to the line joining the points (1, 4, 2) and (2, 3, 5). Find also the perpendicular distance of the origin from this plane

10Page 19

Find the vector equation of the plane which is at a distance of \[\frac{6}{\sqrt{29}}\] from the origin and its normal vector from the origin is  \[2 \hat{i} - 3 \hat{j} + 4 \hat{k} .\] Also, find its Cartesian form. 

 
11Page 19

Find the distance of the plane 2x − 3y + 4z − 6 = 0 from the origin.

 
Exercise 29.05 [Pages 22 - 23]

RD Sharma solutions for Mathematics [English] Class 12 29 The Plane Exercise 29.05 [Pages 22 - 23]

1Page 22

Find the vector equation of the plane passing through the points (1, 1, 1), (1, −1, 1) and (−7, −3, −5).

2Page 23

Find the vector equation of the plane passing through the points P (2, 5, −3), Q (−2, −3, 5) and R (5, 3, −3).

3Page 23

Find the vector equation of the plane passing through points A (a, 0, 0), B (0, b, 0) and C(0, 0, c). Reduce it to normal form. If plane ABC is at a distance p from the origin, prove that \[\frac{1}{p^2} = \frac{1}{a^2} + \frac{1}{b^2} + \frac{1}{c^2} .\]

 

4Page 23

Find the vector equation of the plane passing through the points (1, 1, −1), (6, 4, −5) and (−4, −2, 3).

5Page 23

Find the vector equation of the plane passing through the points \[3 \hat{i}  + 4 \hat{j}  + 2 \hat{k} , 2 \hat{i} - 2 \hat{j} - \hat{k}  \text{ and }  7 \hat{i}  + 6 \hat{k}  .\]

 
Exercise 29.06 [Page 29]

RD Sharma solutions for Mathematics [English] Class 12 29 The Plane Exercise 29.06 [Page 29]

1.1Page 29

Find the angle between the given planes. \[\vec{r} \cdot \left( 2 \hat{i} - 3 \hat{j} + 4 \hat{k} \right) = 1 \text{ and } \vec{r} \cdot \left( - \hat{i}  + \hat{j}  \right) = 4\]

 

1.2Page 29

Find the angle between the given planes. \[\vec{r} \cdot \left( 2 \hat{i} - \hat{j}  + 2 \hat{k}  \right) = 6 \text{ and } \vec{r} \cdot \left( 3 \hat{i}  + 6 \hat{j}  - 2 \hat{k}  \right) = 9\]

1.3Page 29
Find the angle between the given planes.
\[\vec{r} \cdot \left( 2 \hat{i} + 3 \hat{j}  - 6 \hat{k}  \right) = 5 \text{ and } \vec{r} \cdot \left( \hat{i}  - 2 \hat{j}  + 2 \hat{k}  \right) = 9\]

 

2.1Page 29

Find the angle between the planes.

2x − y + z = 4 and x + y + 2z = 3

2.2Page 29

Find the angle between the planes.

x + y − 2z = 3 and 2x − 2y + z = 5

2.3Page 29

Find the angle between the planes.

 x − y + z = 5 and x + 2y + z = 9

2.4Page 29

Find the angle between the planes.
 2x − 3y + 4z = 1 and − x + y = 4

2.5Page 29

Find the angle between the planes.

 2x + y − 2z = 5 and 3x − 6y − 2z = 7

 
3.1Page 29

Show that the following planes are at right angles.

\[\vec{r} \cdot \left( 2 \hat{i} - \hat{j} + \hat{k}  \right) = 5 \text{ and }  \vec{r} \cdot \left( - \hat{i}  - \hat{j} + \hat{k}  \right) = 3\]

 

3.2Page 29

Show that the following planes are at right angles.

x − 2y + 4z = 10 and 18x + 17y + 4z = 49

 

 

4.1Page 29

Determine the value of λ for which the following planes are perpendicular to each other.

\[\vec{r} \cdot \left( \hat{i}  + 2 \hat{j} + 3 \hat{k} \right) = 7 \text{ and }  \vec{r} \cdot \left( \lambda \hat{i} + 2 \hat{j}  - 7 \hat{k}  \right) = 26\]

 

4.2Page 29

Determine the value of λ for which the following planes are perpendicular to each ot

 2x − 4y + 3z = 5 and x + 2y + λz = 5

4.3Page 29

Determine the value of λ for which the following planes are perpendicular to each other. 

 3x − 6y − 2z = 7 and 2x + y − λz = 5

 
5Page 29

Find the equation of a plane passing through the point (−1, −1, 2) and perpendicular to the planes 3x + 2y − 3z = 1 and 5x − 4y + z = 5.

 
6Page 29

Obtain the equation of the plane passing through the point (1, −3, −2) and perpendicular to the planes x + 2y + 2z = 5 and 3x + 3y + 2z = 8.

 
7Page 29

Find the equation of the plane passing through the origin and perpendicular to each of the planes x + 2y − z = 1 and 3x − 4y + z = 5.

 
8Page 29

Find the equation of the plane passing through the points (1, −1, 2) and (2, −2, 2) and which is perpendicular to the plane 6x − 2y + 2z = 9.

 
9Page 29

Find the equation of the plane passing through the points (2, 2, 1) and (9, 3, 6) and perpendicular to the plane 2x + 6y + 6z = 1.

 
10Page 29

Find the equation of the plane passing through the points whose coordinates are (−1, 1, 1) and (1, −1, 1) and perpendicular to the plane x + 2y + 2z = 5.

 
11Page 29

Find the equation of the plane with intercept 3 on the y-axis and parallel to the ZOX plane.

 
12Page 29

Find the equation of the plane that contains the point (1, −1, 2) and is perpendicular to each of the planes 2x + 3y − 2z = 5 and x + 2y − 3z = 8.

13Page 29

Find the equation of the plane passing through (abc) and parallel to the plane  \[\vec{r} \cdot \left( \hat{i}  + \hat{j}  + \hat{k}  \right) = 2 .\]

 
14Page 29

Find the equation of the plane passing through the point (−1, 3, 2) and perpendicular to each of the planes x + 2y + 3z = 5 and 3x + 3y + z = 0.

 
15Page 29

Find the vector equation of the plane through the points (2, 1, −1) and (−1, 3, 4) and perpendicular to the plane x − 2y + 4z = 10 

Exercise 29.07 [Page 33]

RD Sharma solutions for Mathematics [English] Class 12 29 The Plane Exercise 29.07 [Page 33]

1.1Page 33

Find the vector equations of the following planes in scalar product form  \[\left( \vec{r} \cdot \vec{n} = d \right):\] \[\vec{r} = \left( 2 \hat{i} - \hat{k} \right) + \lambda \hat{i} + \mu\left( \hat{i} - 2 \hat{j} - \hat{k}
\right)\]

 
1.2Page 33

Find the vector equations of the following planes in scalar product form  \[\left( \vec{r} \cdot \vec{n} = d \right):\] \[\vec{r} = \left( 1 + s - t \right) \hat{t}  + \left( 2 - s \right) \hat{j}  + \left( 3 - 2s + 2t \right) \hat{k} \]

 
1.3Page 33

Find the vector equations of the following planes in scalar product form  \[\left( \vec{r} \cdot \vec{n} = d \right):\]\[\vec{r} = \left( \hat{i}  + \hat{j}  \right) + \lambda\left( \hat{i}  + 2 \hat{j}  - \hat{k}  \right) + \mu\left( - \hat{i}  + \hat{j} - 2 \hat{k} \right)\]

1.4Page 33

Find the vector equations of the following planes in scalar product form  \[\left( \vec{r} \cdot \vec{n} = d \right):\]\[\vec{r} = \hat{i} - \hat{j} + \lambda\left( \hat{i}  + \hat{j}  + \hat{k}  \right) + \mu\left( 4 \hat{i}  - 2 \hat{j}  + 3 \hat{k} \right)\]

 

2.1Page 33

Find the Cartesian forms of the equations of the following planes. \[\vec{r} = \left( \hat{i}  - \hat{j}  \right) + s\left( - \hat{i}  + \hat{j}  + 2 \hat{k} \right) + t\left( \hat{i} + 2 \hat{j} + \hat{k}  \right)\]

2.2Page 33

Find the Cartesian forms of the equations of the following planes.

\[\vec{r} = \left( 1 + s + t \right) \hat{i}  + \left( 2 - s + t \right) \hat{i}  + \left( 3 - 2s + 2t \right) \hat{k}\]

 

3.1Page 33

Find the vector equation of the following planes in non-parametric form. \[\vec{r} = \left( \lambda - 2\mu \right) \hat{i} + \left( 3 - \mu \right) \hat{j}  + \left( 2\lambda + \mu \right) \hat{k} \]

3.2Page 33

Find the vector equation of the following planes in non-parametric form. \[\vec{r} = \left( 2 \hat{i}  + 2 \hat{j}  - \hat{k}  \right) + \lambda\left( \hat{i}  + 2 \hat{j}  + 3 \hat{k}  \right) + \mu\left( 5 \hat{i}  - 2 \hat{j} + 7 \hat{k}  \right)\]

 

Exercise 29.08 [Pages 39 - 40]

RD Sharma solutions for Mathematics [English] Class 12 29 The Plane Exercise 29.08 [Pages 39 - 40]

1Page 39

Find the equation of the plane which is parallel to 2x − 3y + z = 0 and which passes through (1, −1, 2).

2Page 39

Find the equation of the plane through (3, 4, −1) which is parallel to the plane \[\vec{r} \cdot \left( 2 \hat{i} - 3 \hat{j}  + 5 \hat{k} \right) + 2 = 0 .\]

 
3Page 39

Find the equation of the plane passing through the line of intersection of the planes 2x − 7y + 4z − 3 = 0, 3x − 5y + 4z + 11 = 0 and the point (−2, 1, 3).

4Page 39

Find the equation of the plane through the point \[2 \hat{i}  + \hat{j} - \hat{k} \] and passing through the line of intersection of the planes \[\vec{r} \cdot \left( \hat{i} + 3 \hat{j} - \hat{k}  \right) = 0 \text{ and }  \vec{r} \cdot \left( \hat{j} + 2 \hat{k}  \right) = 0 .\]

 
5Page 39

Find the equation of the plane passing through the line of intersection of the planes 2x − y = 0 and 3z − y = 0 and perpendicular to the plane 4x + 5y − 3z = 8

6Page 39

Find the equation of the plane which contains the line of intersection of the planes x + 2y + 3z − 4 = 0 and 2x + y − z + 5 = 0 and which is perpendicular to the plane 5x + 3y − 6z+ 8 = 0.

7Page 39

Find the equation of the plane through the line of intersection of the planes x + 2y + 3z + 4 = 0 and x − y + z + 3 = 0 and passing through the origin.

 
8Page 39

Find the vector equation (in scalar product form) of the plane containing the line of intersection of the planes x − 3y + 2z − 5 = 0 and 2x − y + 3z − 1 = 0 and passing through (1, −2, 3).

9Page 39

Find the equation of the plane that is perpendicular to the plane 5x + 3y + 6z + 8 = 0 and which contains the line of intersection of the planes x + 2y + 3z − 4 = 0, 2x + y − z + 5 = 0.

 
10Page 39

Find the equation of the plane through the line of intersection of the planes  \[\vec{r} \cdot \left( \hat{i} + 3 \hat{j} \right) + 6 = 0  \text{ and } \vec{r} \cdot \left( 3 \hat{i} - \hat{j}  - 4 \hat{k}  \right) = 0,\] which is at a unit distance from the origin.

 
11Page 39

Find the equation of the plane passing through the intersection of the planes 2x + 3y − z+ 1 = 0 and x + y − 2z + 3 = 0 and perpendicular to the plane 3x − y − 2z − 4 = 0.

 
12Page 39

Find the equation of the plane that contains the line of intersection of the planes  \[\vec{r} \cdot \left( \hat{i}  + 2 \hat{j}  + 3 \hat{k}  \right) - 4 = 0 \text{ and }  \vec{r} \cdot \left( 2 \hat{i}  + \hat{j} - \hat{k}  \right) + 5 = 0\] and which is perpendicular  to the plane \[\vec{r} \cdot \left( 5 \hat{i}  + 3 \hat{j}  - 6 \hat{k}  \right) + 8 = 0 .\]

  
13Page 39

Find the equation of the plane passing through (abc) and parallel to the plane \[\vec{r} \cdot \left( \hat{i} + \hat{j} + \hat{k}  \right) = 2 .\]

 
14Page 39

Find the equation of the plane passing through the intersection of the planes  \[\vec{r} \cdot \left( 2 \hat{i} + \hat{j}  + 3 \hat{k}  \right) = 7, \vec{r} \cdot \left( 2 \hat{i}  + 5 \hat{j} + 3 \hat{k}  \right) = 9\] and the point (2, 1, 3).

 
15Page 40

Find the equation of the plane through the intersection of the planes 3x − y + 2z = 4 and x + y + z = 2 and the point (2, 2, 1).

16Page 40

Find the vector equation of the plane through the line of intersection of the planes x + yz = 1 and 2x + 3y + 4z = 5 which is perpendicular to the plane x − y + z = 0.

 
17Page 40

Find the vector equation of the plane passing through the intersection of the planes

\[\vec{r} \cdot \left( \hat{ i } + \hat{ j }+ \hat{ k }\right) = \text{ 6 and }\vec{r} \cdot \left( \text{ 2  } \hat{ i} +\text{  3 } \hat{  j } + \text{ 4 } \hat{ k } \right) = - 5\] and the point (1, 1, 1).

18Page 40

Find the equation of the plane which contains the line of intersection of the planes x \[+\]  2y \[+\]  3 \[z   - \]  4 \[=\]  0 and 2 \[x + y - z\] \[+\] 5  \[=\] 0 and whose x-intercept is twice its z-intercept. Hence, write the equation of the plane passing through the point (2, 3,  \[-\] 1) and parallel to the plane obtained above.

19Page 40

Find the equation of the plane through the line of intersection of the planes \[x + y + z =\]1 and 2x \[+\] 3 \[+\] y \[+\] 4\[z =\] 5 and twice of its \[y\] -intercept is equal to three times its \[z\]-intercept

 
Exercise 29.09 [Page 49]

RD Sharma solutions for Mathematics [English] Class 12 29 The Plane Exercise 29.09 [Page 49]

1Page 49

Find the distance of the point  \[2 \hat{i} - \hat{j} - 4 \hat{k}\]  from the plane  \[\vec{r} \cdot \left( 3 \hat{i}  - 4 \hat{j}  + 12 \hat{k}  \right) - 9 = 0 .\]

2Page 49

Show that the points \[\hat{i}  - \hat{j}  + 3 \hat{k}  \text{ and }  3 \hat{i}  + 3 \hat{j}  + 3 \hat{k} \] are equidistant from the plane \[\vec{r} \cdot \left( 5 \hat{i}  + 2 \hat{j}  - 7 \hat{k}  \right) + 9 = 0 .\]

  
3Page 49

Find the distance of the point (2, 3, −5) from the plane x + 2y − 2z − 9 = 0.

 
4Page 49

Find the equations of the planes parallel to the plane x + 2y − 2z + 8 = 0 that are at a distance of 2 units from the point (2, 1, 1).

 
5Page 49

Show that the points (1, 1, 1) and (−3, 0, 1) are equidistant from the plane 3x + 4y − 12z + 13 = 0.

 
6Page 49

Find the equations of the planes parallel to the plane x − 2y + 2z − 3 = 0 and which are at a unit distance from the point (1, 1, 1).

 
7Page 49

Find the distance of the point (2, 3, 5) from the xy - plane.

 
8Page 49

Find the distance of the point (3, 3, 3) from the plane \[\vec{r} \cdot \left( 5 \hat{i}  + 2 \hat{j}  - 7k \right) + 9 = 0\]

 
9Page 49

If the product of the distances of the point (1, 1, 1) from the origin and the plane x − y + z+ λ = 0 be 5, find the value of λ.

10Page 49

Find an equation for the set of all points that are equidistant from the planes 3x − 4y + 12z = 6 and 4x + 3z = 7.

 
11Page 49

Find the distance between the point (7, 2, 4) and the plane determined by the points A(2, 5, −3), B(−2, −3, 5) and C (5, 3, −3). 

12Page 49

A plane makes intercepts −6, 3, 4 respectively on the coordinate axes. Find the length of the perpendicular from the origin on it.

13Page 49

Find the distance of the point (1, -2, 4) from plane passing throuhg the point (1, 2, 2) and perpendicular of the planes x - y + 2z = 3 and 2x - 2y + z + 12 = 0 

Exercise 29.10 [Page 51]

RD Sharma solutions for Mathematics [English] Class 12 29 The Plane Exercise 29.10 [Page 51]

1Page 51

Find the distance between the parallel planes 2x − y + 3z − 4 = 0 and 6x − 3y + 9z + 13 = 0.

2Page 51

Find the equation of the plane which passes through the point (3, 4, −1) and is parallel to the plane 2x − 3y + 5z + 7 = 0. Also, find the distance between the two planes.

 
3Page 51

Find the equation of the plane mid-parallel to the planes 2x − 2y + z + 3 = 0 and 2x − 2y + z + 9 = 0.

 
4Page 51

Find the distance between the planes \[\vec{r} \cdot \left( \hat{i}  + 2 \hat{j}  + 3 \hat{k}  \right) + 7 = 0 \text{ and } \vec{r} \cdot \left( 2 \hat{i}  + 4 \hat{j}  + 6 \hat{k}  \right) + 7 = 0 .\]

 
Exercise 29.11 [Pages 61 - 62]

RD Sharma solutions for Mathematics [English] Class 12 29 The Plane Exercise 29.11 [Pages 61 - 62]

1Page 61

Find the angle between the line \[\vec{r} = \left( 2 \hat{i}+ 3 \hat {j}  + 9 \hat{k}  \right) + \lambda\left( 2 \hat{i} + 3 \hat{j}  + 4 \hat{k}  \right)\]  and the plane  \[\vec{r} \cdot \left( \hat{i}  + \hat{j}  + \hat{k}  \right) = 5 .\]

 
2Page 61

Find the angle between the line \[\frac{x - 1}{1} = \frac{y - 2}{- 1} = \frac{z + 1}{1}\]  and the plane 2x + y − z = 4.

  
3Page 61

Find the angle between the line joining the points (3, −4, −2) and (12, 2, 0) and the plane 3x − y + z = 1.

 
4Page 61

The line  \[\vec{r} = \hat{i} + \lambda\left( 2 \hat{i} - m \hat{j}  - 3 \hat{k}  \right)\]  is parallel to the plane  \[\vec{r} \cdot \left( m \hat{i}  + 3 \hat{j}  + \hat{k}  \right) = 4 .\] Find m

 
5Page 61

Show that the line whose vector equation is \[\vec{r} = 2 \hat{i}  + 5 \hat{j} + 7 \hat{k}+ \lambda\left( \hat{i}  + 3 \hat{j}  + 4 \hat{k}  \right)\] is parallel to the plane whose vector  \[\vec{r} \cdot \left( \hat{i} + \hat{j}  - \hat{k}  \right) = 7 .\]  Also, find the distance between them.

  
6Page 61

Find the vector equation of the line through the origin which is perpendicular to the plane  \[\vec{r} \cdot \left( \hat{i} + 2 \hat{j}  + 3 \hat{k}  \right) = 3 .\]

 
7Page 61

Find the equation of the plane through (2, 3, −4) and (1, −1, 3) and parallel to x-axis.

 
8Page 61

Find the equation of a plane passing through the points (0, 0, 0) and (3, −1, 2) and parallel to the line \[\frac{x - 4}{1} = \frac{y + 3}{- 4} = \frac{z + 1}{7} .\]

 
9Page 61

Find the vector and Cartesian equations of the line passing through (1, 2, 3) and parallel to the planes \[\vec{r} \cdot \left( \hat{i}  - \hat{j} + 2 \hat{k}  \right) = 5 \text{ and } \vec{r} \cdot \left( 3 \hat{i} + \hat{j}  + 2 \hat{k} \right) = 6\]

 
10Page 61

Prove that the line of section of the planes 5x + 2y − 4z + 2 = 0 and 2x + 8y + 2z − 1 = 0 is parallel to the plane 4x − 2y − 5z − 2 = 0.

 
11Page 61

Find the vector equation of the line passing through the point (1, −1, 2) and perpendicular to the plane 2x − y + 3z − 5 = 0.

 
12Page 61

Find the equation of the plane through the points (2, 2, −1) and (3, 4, 2) and parallel to the line whose direction ratios are 7, 0, 6.

 
13Page 61

Find the angle between the line \[\frac{x - 2}{3} = \frac{y + 1}{- 1} = \frac{z - 3}{2}\] and the plane

3x + 4y + z + 5 = 0.

  
14Page 61

Find the equation of the plane passing through the intersection of the planes x − 2y + z = 1 and 2x + y + z = 8 and parallel to the line with direction ratios proportional to 1, 2, 1. Also, find the perpendicular distance of (1, 1, 1) from this plane

15Page 61

State when the line \[\vec{r} = \vec{a} + \lambda \vec{b}\]  is parallel to the plane  \[\vec{r} \cdot \vec{n} = d .\]Show that the line  \[\vec{r} = \hat{i}  + \hat{j}  + \lambda\left( 3 \hat{i}  - \hat{j}  + 2 \hat{k}  \right)\]  is parallel to the plane  \[\vec{r} \cdot \left( 2 \hat{j} + \hat{k} \right) = 3 .\]   Also, find the distance between the line and the plane.

 
 
16Page 61

Show that the plane whose vector equation is \[\vec{r} \cdot \left( \hat{i}  + 2 \hat{j}  - \hat{k}  \right) = 1\] and the line whose vector equation is  \[\vec{r} = \left( - \hat{i}  + \hat{j} + \hat{k}  \right) + \lambda\left( 2 \hat{i}  + \hat{j}  + 4 \hat{k}  \right)\]   are parallel. Also, find the distance between them. 

17Page 61

Find the equation of the plane through the intersection of the planes 3x − 4y + 5z = 10 and 2x + 2y − 3z = 4 and parallel to the line x = 2y = 3z.

 
18Page 62

Find the vector and Cartesian forms of the equation of the plane passing through the point (1, 2, −4) and parallel to the lines \[\vec{r} = \left( \hat{i} + 2 \hat{j}  - 4 \hat{k}  \right) + \lambda\left( 2 \hat{i}  + 3 \hat{j}  + 6 \hat{k}  \right)\] and \[\vec{r} = \left( \hat{i}  - 3 \hat{j}  + 5 \hat{k}  \right) + \mu\left( \hat{i}  + \hat{j}  - \hat{k} \right)\] Also, find the distance of the point (9, −8, −10) from the plane thus obtained.  

 

19Page 62

Find the equation of the plane passing through the points (3, 4, 1) and (0, 1, 0) and parallel to the line 

\[\frac{x + 3}{2} = \frac{y - 3}{7} = \frac{z - 2}{5} .\]
  
20Page 62

Find the coordinates of the point where the line  \[\frac{x - 2}{3} = \frac{y + 1}{4} = \frac{z - 2}{2}\]   intersects the plane x − y + z − 5 = 0. Also, find the angle between the line and the plane. 

 
21Page 62

Find the vector equation of the line passing through (1, 2, 3) and perpendicular to the plane \[\vec{r} \cdot \left( \hat{i}  + 2 \hat{j}  - 5 \hat{k}  \right) + 9 = 0 .\]

 
22Page 62

Find the angle between the line

\[\frac{x + 1}{2} = \frac{y}{3} = \frac{z - 3}{6}\]  and the plane 10x + 2y − 11z = 3.
 
23Page 62

Find the vector equation of the line passing through (1, 2, 3) and parallel to the planes  \[\vec{r} \cdot \left( \hat{i}  - \hat{j}  + 2 \hat{k}  \right) = 5 \text{ and } \vec{r} \cdot \left( 3 \hat{i}  + \hat{j}  + \hat{k}  \right) = 6 .\]

 

24Page 62

Find the value of λ such that the line \[\frac{x - 2}{6} = \frac{y - 1}{\lambda} = \frac{z + 5}{- 4}\]  is perpendicular to the plane 3x − y − 2z = 7.

 
 
25Page 62

Find the equation of the plane passing through the points (−1, 2, 0), (2, 2, −1) and parallel to the line \[\frac{x - 1}{1} = \frac{2y + 1}{2} = \frac{z + 1}{- 1}\]

 
Exercise 29.12 [Page 65]

RD Sharma solutions for Mathematics [English] Class 12 29 The Plane Exercise 29.12 [Page 65]

1.1Page 65

Find the coordinates of the point where the line through (5, 1, 6) and (3, 4, 1) crosses the   yz - plane .

1.2Page 65

Find the coordinates of the point where the line through (5, 1, 6) and (3, 4, 1) crosses the  zx - plane .

2Page 65

Find the coordinates of the point where the line through (3, −4, −5) and (2, −3, 1) crosses the plane 2x + y + z = 7.

 
3Page 65

Find the distance of the point (−1, −5, −10) from the point of intersection of the line \[\vec{r} = \left( 2 \hat{i}  - \hat{j} + 2 \hat{k}  \right) + \lambda\left( 3 \hat{i}+ 4 \hat{j} + 2 \hat{k}  \right)\] and the plane  \[\vec{r} . \left( \hat{i}  - \hat{j}  + \hat{k} \right) = 5 .\]

 
4Page 65

Find the distance of the point (2, 12, 5) from the point of intersection of the line \[\vec{r} = 2 \hat{i}  - 4 \hat{j}+ 2 \hat{k}  + \lambda\left( 3 \hat{i}  + 4 \hat{j}  + 2 \hat{k} \right)\] and \[\vec{r} . \left( \hat{i}  - 2 \hat{j}  + \hat{k}  \right) = 0\]

  
5Page 65

Find the distance of the point P(−1, −5, −10) from the point of intersection of the line joining the points A(2, −1, 2) and B(5, 3, 4) with the plane  \[x - y + z = 5\] . 

 

6Page 65

Find the distance of the point P(3, 4, 4) from the point, where the line joining the points A(3, –4, –5) and B(2, –3, 1) intersects the plane 2x + y + z = 7.

7Page 65

Find the distance of the point (1, -5, 9) from the plane

\[x - y + z =\] 5  measured along the line \[x = y = z\]  . 
 
Exercise 29.13 [Pages 73 - 74]

RD Sharma solutions for Mathematics [English] Class 12 29 The Plane Exercise 29.13 [Pages 73 - 74]

1Page 73

Show that the lines \[\vec{r} = \left( 2 \hat{j}  - 3 \hat{k} \right) + \lambda\left( \hat{i}  + 2 \hat{j}  + 3 \hat{k} \right) \text{ and } \vec{r} = \left( 2 \hat{i}  + 6 \hat{j} + 3 \hat{k} \right) + \mu\left( 2 \hat{i}  + 3 \hat{j} + 4 \hat{k}  \right)\]  are coplanar. Also, find the equation of the plane containing them.

 
 
2Page 74

Show that the lines \[\frac{x + 1}{- 3} = \frac{y - 3}{2} = \frac{z + 2}{1} \text{ and }\frac{x}{1} = \frac{y - 7}{- 3} = \frac{z + 7}{2}\]  are coplanar. Also, find the equation of the plane containing them. 

 
3Page 74

Find the equation of the plane containing the line \[\frac{x + 1}{- 3} = \frac{y - 3}{2} = \frac{z + 2}{1}\]  and the point (0, 7, −7) and show that the line  \[\frac{x}{1} = \frac{y - 7}{- 3} = \frac{z + 7}{2}\] also lies in the same plane.

 
4Page 74

Find the equation of the plane which contains two parallel lines\[\frac{x - 4}{1} = \frac{y - 3}{- 4} = \frac{z - 2}{5}\text{  and }\frac{x - 3}{1} = \frac{y + 2}{- 4} = \frac{z}{5} .\]

5Page 74

Show that the lines  \[\frac{x + 4}{3} = \frac{y + 6}{5} = \frac{z - 1}{- 2}\] and 3x − 2y + z + 5 = 0 = 2x + 3y + 4z − 4 intersect. Find the equation of the plane in which they lie and also their point of intersection.

  
6Page 74

Show that the plane whose vector equation is \[\vec{r} \cdot \left( \hat{i}  + 2 \hat{j} - \hat{k}  \right) = 3\] contains the line whose vector equation is \[\vec{r} = \hat{i} + \hat{j}  + \lambda\left( 2 \hat{i}  + \hat{j} + 4 \hat{k}  \right) .\]

 
7Page 74

Find the equation of the plane determined by the intersection of the lines \[\frac{x + 3}{3} = \frac{y}{- 2} = \frac{z - 7}{6} \text{ and  }\frac{x + 6}{1} = \frac{y + 5}{- 3} = \frac{z - 1}{2}\]

 
8Page 74

Find the vector equation of the plane passing through the points (3, 4, 2) and (7, 0, 6) and perpendicular to the plane 2x − 5y − 15 = 0. Also, show that the plane thus obtained contains the line \[\vec{r} = \hat{i} + 3 \hat{j}  - 2 \hat{k}  + \lambda\left( \hat{i}  - \hat{j}  + \hat{k}  \right) .\]

 
9Page 74

If the lines  \[\frac{x - 1}{- 3} = \frac{y - 2}{- 2k} = \frac{z - 3}{2} \text{ and }\frac{x - 1}{k} = \frac{y - 2}{1} = \frac{z - 3}{5}\] are perpendicular, find the value of and, hence, find the equation of the plane containing these lines.

10Page 74

Find the coordinates of the point where the line \[\frac{x - 2}{3} = \frac{y + 1}{4} = \frac{z - 2}{2}\] intersect the plane x − y + z − 5 = 0. Also, find the angle between the line and the plane.

  
11Page 74

Find the vector equation of the plane passing through three points with position vectors  \[\hat{i}  + \hat{j}  - 2 \hat{k}  , 2 \hat{i}  - \hat{j}  + \hat{k}  \text{ and }  \hat{i}  + 2 \hat{j}  + \hat{k}  .\]  Also, find the coordinates of the point of intersection of this plane and the line  \[\vec{r} = 3 \hat{i}  - \hat{j}  - \hat{k}  + \lambda\left( 2 \hat{i}  - 2 \hat{j} + \hat{k} \right) .\]

 
12Page 74

Show that the lines  \[\frac{5 - x}{- 4} = \frac{y - 7}{4} = \frac{z + 3}{- 5}\] and  \[\frac{x - 8}{7} = \frac{2y - 8}{2} = \frac{z - 5}{3}\] are coplanar.

 
13Page 74

Find the equation of a plane which passes through the point (3, 2, 0) and contains the line  \[\frac{x - 3}{1} = \frac{y - 6}{5} = \frac{z - 4}{4}\] .

 

14Page 74

Show that the lines  \[\frac{x + 3}{- 3} = \frac{y - 1}{1} = \frac{z - 5}{5}\] and  \[\frac{x + 1}{- 1} = \frac{y - 2}{2} = \frac{z - 5}{5}\]  are coplanar. Hence, find the equation of the plane containing these lines.

 
15Page 74

 If the line \[\frac{x - 3}{2} = \frac{y + 2}{- 1} = \frac{z + 4}{3}\]  lies in the plane  \[lx + my - z =\]   then find the value of  \[l^2 + m^2\] .

  
16Page 74

Find the values of  \[\lambda\] for which the lines

\[\frac{x - 1}{1} = \frac{y - 2}{2} = \frac{z + 3}{\lambda^2}\]and  \[\frac{x - 3}{1} = \frac{y - 2}{\lambda^2} = \frac{z - 1}{2}\]  are coplanar . 
17Page 74

If the lines  \[x =\]  5 ,  \[\frac{y}{3 - \alpha} = \frac{z}{- 2}\] and   \[x = \alpha\] \[\frac{y}{- 1} = \frac{z}{2 - \alpha}\] are coplanar, find the values of  \[\alpha\].

 

18Page 74

If the straight lines  \[\frac{x - 1}{2} = \frac{y + 1}{k} = \frac{z}{2}\] and \[\frac{x + 1}{2} = \frac{y + 1}{2} = \frac{z}{k}\] are coplanar, find the equations of the planes containing them.

 

Exercise 29.14 [Page 77]

RD Sharma solutions for Mathematics [English] Class 12 29 The Plane Exercise 29.14 [Page 77]

1Page 77

Find the shortest distance between the lines

\[\frac{x - 2}{- 1} = \frac{y - 5}{2} = \frac{z - 0}{3} \text{ and }  \frac{x - 0}{2} = \frac{y + 1}{- 1} = \frac{z - 1}{2} .\]
 
2Page 77

Find the shortest distance between the lines 

\[\frac{x + 1}{7} = \frac{y + 1}{- 6} = \frac{z + 1}{1} \text{ and } \frac{x - 3}{1} = \frac{y - 5}{- 2} = \frac{z - 7}{1} .\]
 
3Page 77

Find the shortest distance between the lines

\[\frac{x - 1}{2} = \frac{y - 3}{4} = \frac{z + 2}{1}\] and
\[3x - y - 2z + 4 = 0 = 2x + y + z + 1\]
 
Exercise 29.15 [Pages 81 - 82]

RD Sharma solutions for Mathematics [English] Class 12 29 The Plane Exercise 29.15 [Pages 81 - 82]

1Page 81

Find the image of the point (0, 0, 0) in the plane 3x + 4y − 6z + 1 = 0.

 
2Page 81

Find the reflection of the point (1, 2, −1) in the plane 3x − 5y + 4z = 5.

 
3Page 81

Find the coordinates of the foot of the perpendicular drawn from the point (5, 4, 2) to the line \[\frac{x + 1}{2} = \frac{y - 3}{3} = \frac{z - 1}{- 1} .\]

 Hence, or otherwise, deduce the length of the perpendicular.

 
 
4Page 81

Find the image of the point with position vector \[3 \hat{i} + \hat{j}  + 2 \hat{k} \]  in the plane  \[\vec{r} \cdot \left( 2 \hat{i} - \hat{j}  + \hat{k}  \right) = 4 .\]  Also, find the position vectors of the foot of the perpendicular and the equation of the perpendicular line through \[3 \hat{i}  + \hat{j}  + 2 \hat{k} .\]

 
 
5Page 81

Find the coordinates of the foot of the perpendicular from the point (1, 1, 2) to the plane 2x − 2y + 4z + 5 = 0. Also, find the length of the perpendicular.

 
6Page 82

Find the distance of the point (1, −2, 3) from the plane x − y + z = 5 measured along a line parallel to  \[\frac{x}{2} = \frac{y}{3} = \frac{z}{- 6} .\]

 

7Page 82

Find the coordinates of the foot of the perpendicular from the point (2, 3, 7) to the plane 3x − y − z = 7. Also, find the length of the perpendicular.

8Page 82

Find the image of the point (1, 3, 4) in the plane 2x − y + z + 3 = 0.

 
9Page 82

Find the distance of the point with position vector

\[- \hat{i}  - 5 \hat{j}  - 10 \hat{k} \]  from the point of intersection of the line \[\vec{r} = \left( 2 \hat{i}  - \hat{j}  + 2 \hat{k}  \right) + \lambda\left( 3 \hat{i}  + 4 \hat{j}  + 12 \hat{k}  \right)\]  with the plane \[\vec{r} \cdot \left( \hat{i} - \hat{j}+ \hat{k}  \right) = 5 .\]
 
10Page 82

Find the length and the foot of the perpendicular from the point (1, 1, 2) to the plane \[\vec{r} \cdot \left( \hat{i}  - 2 \hat{j}  + 4 \hat{k}  \right) + 5 = 0 .\]

 
11Page 82

Find the coordinates of the foot of the perpendicular and the perpendicular distance of the  point P (3, 2, 1) from the plane 2x − y + z + 1 = 0. Also, find the image of the point in the plane.

12Page 82

Find the direction cosines of the unit vector perpendicular to the plane  \[\vec{r} \cdot \left( 6 \hat{i}  - 3 \hat{j} - 2 \hat{k} \right) + 1 = 0\] passing through the origin.

 
13Page 82

Find the coordinates of the foot of the perpendicular drawn from the origin to the plane 2x − 3y + 4z − 6 = 0.

14Page 82

Find the length and the foot of perpendicular from the point \[\left( 1, \frac{3}{2}, 2 \right)\]  to the plane \[2x - 2y + 4z + 5 = 0\] .

 
15Page 82

Find the position vector of the foot of perpendicular and the perpendicular distance from the point P with position vector \[2 \hat{i}  + 3 \hat{j}  + 4 \hat{k} \] to the plane  \[\vec{r} . \left( 2 \hat{i} + \hat{j}  + 3 \hat{k}  \right) - 26 = 0\] Also find image of P in the plane.

 
Very Short Answers [Pages 83 - 84]

RD Sharma solutions for Mathematics [English] Class 12 29 The Plane Very Short Answers [Pages 83 - 84]

1Page 83

Write the equation of the plane parallel to XOY- plane and passing through the point (2, −3, 5).

 
2Page 83

Write the equation of the plane parallel to the YOZ- plane and passing through (−4, 1, 0).

 
3Page 83

Write the equation of the plane passing through points (a, 0, 0), (0, b, 0) and (0, 0, c).

 
4Page 83

Write the general equation of a plane parallel to X-axis.

 
5Page 83

Write the value of k for which the planes x − 2y + kz = 4 and 2x + 5y − z = 9 are perpendicular.

 
6Page 83

Write the intercepts made by the plane 2x − 3y + 4z = 12 on the coordinate axes.

 
7Page 83

Write the ratio in which the plane 4x + 5y − 3z = 8 divides the line segment joining the points (−2, 1, 5) and (3, 3, 2).

 
8Page 83

Write the distance between the parallel planes 2x − y + 3z = 4 and 2x − y + 3z = 18.  

9Page 83

Write the plane  \[\vec{r} \cdot \left( 2 \hat{i}  + 3 \hat{j}  - 6 \hat{k}  \right) = 14\]  in normal form.

 
 
10Page 83

Write the distance of the plane  \[\vec{r} \cdot \left( 2 \hat{i} - \hat{j} + 2 \hat{k} \right) = 12\] from the origin.

  
11Page 83

Write the equation of the plane  \[\vec{r} = \vec{a} + \lambda \vec{b} + \mu \vec{c}\]   in scalar product form.

 
12Page 83

Write a vector normal to the plane  \[\vec{r} = l \vec{b} + m \vec{c} .\]

 
13Page 83

Write the equation of the plane passing through (2, −1, 1) and parallel to the plane 3x + 2y −z = 7.

14Page 83

Write the equation of the plane containing the lines \[\vec{r} = \vec{a} + \lambda \vec{b} \text{ and }  \vec{r} = \vec{a} + \mu \vec{c} .\]

 
15Page 83

Write the position vector of the point where the line \[\vec{r} = \vec{a} + \lambda \vec{b}\] meets the plane  \[\vec{r} . \vec{n} = 0 .\]

16Page 83

Write the value of k for which the line \[\frac{x - 1}{2} = \frac{y - 1}{3} = \frac{z - 1}{k}\]  is perpendicular to the normal to the plane  \[\vec{r} \cdot \left( 2 \hat{i}  + 3 \hat{j}  + 4 \hat{k}  \right) = 4 .\]

17Page 84

Write the angle between the line \[\frac{x - 1}{2} = \frac{y - 2}{1} = \frac{z + 3}{- 2}\]  and the plane x + y + 4 = 0. 

 
18Page 84

Write the intercept cut off by the plane 2x + y − z = 5 on x-axis.

 
19Page 84

Find the length of the perpendicular drawn from the origin to the plane 2x − 3y + 6z + 21 = 0.

 
20Page 84

Write the vector equation of the line passing through the point (1, −2, −3) and normal to the plane \[\vec{r} \cdot \left( 2 \hat{i} + \hat{j}  + 2 \hat{k}  \right) = 5 .\]

 
21Page 84

Find the vector equation of the plane, passing through the point (abc) and parallel to the plane \[\vec{r} . \left( \hat{i}  + \hat{j}  + \hat{k}  \right) = 2\]

 
22Page 84

Find the vector equation of a plane which is at a distance of 5 units from the origin and its normal vector is \[2 \hat{i} - 3 \hat{j} + 6 \hat{k} \] .

23Page 84

Write the equation of a plane which is at a distance of \[5\sqrt{3}\] units from origin and the normal to which is equally inclined to coordinate axes.

 
MCQ [Pages 84 - 86]

RD Sharma solutions for Mathematics [English] Class 12 29 The Plane MCQ [Pages 84 - 86]

1Page 84

The plane 2x − (1 + λ) y + 3λz = 0 passes through the intersection of the planes

  • 2x − y = 0 and y − 3z = 0

  • 2x + 3z = 0 and y = 0

  • 2x − y + 3z = 0 and y − 3z = 0

  • None of these

2Page 84

The acute angle between the planes 2x − y + z = 6 and x + y + 2z = 3 is

  •  45°

  • 60°

  •  30°

  •  75°

3Page 84

The equation of the plane through the intersection of the planes x + 2y + 3z = 4 and 2x + y − z = −5 and perpendicular to the plane 5x + 3y + 6z + 8 = 0 is


  • 7x − 2y + 3z + 81 = 0

  • 23x + 14y − 9z + 48 = 0

  •  51x − 15y − 50z + 173 = 0

  •  None of these

     
4Page 84

The distance between the planes 2x + 2y − z + 2 = 0 and 4x + 4y − 2z + 5 = 0 is 

 

 

 

 
 
  • \[\frac{1}{2}\]

  • \[\frac{1}{4}\]

  •  \[\frac{1}{6}\]

  • None of these 

5Page 84

The image of the point (1, 3, 4) in the plane 2x − y + z + 3 = 0 is

  •  (3, 5, 2)

  •  (−3, 5, 2)

  •  (3, 5, −2)

  • (3, −5, 2)

     
6Page 85

The equation of the plane containing the two lines

\[\frac{x - 1}{2} = \frac{y + 1}{- 1} = \frac{z - 0}{3} \text{ and }\frac{x}{- 2} = \frac{y - 2}{- 3} = \frac{z + 1}{- 1}\]
 
 
  •  8x + y − 5z − 7 = 0

  •  8x + y + 5z − 7 = 0

  • 8x − y − 5z − 7 = 0

  •  None of these

     
7Page 85

The equation of the plane \[\vec{r} = \hat{i} - \hat{j}  + \lambda\left( \hat{i}  + \hat{j} + \hat{k}  \right) + \mu\left( \hat{i}  - 2 \hat{j}  + 3 \hat{k}  \right)\]  in scalar product form is

 

 

 

 

 
 
 
  •   \[\vec{r} \cdot \left( 5 \hat{i}  - 2 \hat{j}  - 3 \hat{k}  \right) = 7\]

  •  \[\vec{r} \cdot \left( 5 \hat{i}  + 2 \hat{j}  - 3 \hat{k}  \right) = 7\]

  •  \[\vec{r} \cdot \left( 5 \hat{i}  - 2 \hat{j}  + 3 \hat{k} \right) = 7\]

  •  None of these

8Page 85

The distance of the line \[\vec{r} = 2 \hat{i} - 2 \hat{j} + 3 \hat{k} + \lambda\left( \hat{i} - \hat{j}+ 4 \hat{k}  \right)\]  from the plane \[\vec{r} \cdot \left( \hat{i} + 5 \hat{j} + \hat{k} \right) = 5\] is

 

  • \[\frac{5}{3\sqrt{3}}\]

     

  • \[\frac{10}{3\sqrt{3}}\]

  • \[\frac{25}{3\sqrt{3}}\]

     
  •  None of these

     
9Page 85

The equation of the plane through the line x + y + z + 3 = 0 = 2x − y + 3z + 1 and parallel to the line \[\frac{x}{1} = \frac{y}{2} = \frac{z}{3}\] is 

 

 

  •  x − 5y + 3z = 7

  • x − 5y + 3z = −7

  •  x + 5y + 3z = 7

  •  x + 5y + 3z = −7

     
10Page 85

The vector equation of the plane containing the line \[\vec{r} = \left( - 2 \hat{i} - 3 \hat{j}  + 4 \hat{k}  \right) + \lambda\left( 3 \hat{i}  - 2 \hat{j}  - \hat{k}  \right)\] and the point  \[\hat{i}  + 2 \hat{j}  + 3 \hat{k} \]  is 

 
  • \[\vec{r} \cdot \left( \hat{i} + 3 \hat{k}  \right) = 10\]

     
  •  \[\vec{r} \cdot \left( \hat{i} - 3 \hat{k} \right) = 10\]

     
  •  \[\vec{r} \cdot \left( 3\hat{i} -  \hat{k} \right) = 10\]

  • None of these

     
11Page 85

A plane meets the coordinate axes at AB and C such that the centroid of ∆ABC is the point (abc). If the equation of the plane is \[\frac{x}{a} + \frac{y}{b} + \frac{z}{c} = k,\] then k = 

 

  •  1

  •  2

  •  3

  •  None of these

     
12Page 85
 The distance between the point (3, 4, 5) and the point where the line \[\frac{x - 3}{1} = \frac{y - 4}{2} = \frac{z - 5}{2}\] meets the plane x + y + z = 17 is
  •  1

  • 2

  •  3

  • None of these

     
13Page 85

A vector parallel to the line of intersection of the planes\[\vec{r} \cdot \left( 3 \hat{i} - \hat{j} + \hat{k}  \right) = 1 \text{ and }  \vec{r} \cdot \left( \hat{i} + 4 \hat{j}  - 2 \hat{k}  \right) = 2\] is 

 
  •  \[- 2 \hat{i} + 7 \hat{j}+ 13 \hat{k} \]

  •   \[2 \hat{i}  + 7 \hat{j} - 13 \hat{k}\]

  •  \[-2 \hat{i}  + 7 \hat{j} + 13 \hat{k}\]

  •  \[2 \hat{i}  + 7 \hat{j} + 13 \hat{k}\]

14Page 85

If a plane passes through the point (1, 1, 1) and is perpendicular to the line \[\frac{x - 1}{3} = \frac{y - 1}{0} = \frac{z - 1}{4}\] then its perpendicular distance from the origin is ______.

  • `3/4`

  • `4/3`

  • `7/5`

  •  1

15Page 85

The equation of the plane parallel to the lines x − 1 = 2y − 5 = 2z and 3x = 4y − 11 = 3z − 4 and passing through the point (2, 3, 3) is

  •  x − 4y + 2z + 4 = 0

  • x + 4y + 2z + 4 = 0

  •  x − 4y + 2z − 4 = 0

  • None of these

     
16Page 86

The distance of the point (−1, −5, −10) from the point of intersection of the line \[\vec{r} = 2 \hat{i}- \hat{j} + 2 \hat{k}  + \lambda\left( 3 \hat{i}  + 4 \hat{j}+ 12 \hat{k}  \right)\]   and the plane \[\vec{r} \cdot \left( \hat{i} - \hat{j} + \hat{k}  \right) = 5\] is 

 
 
  • 9

  •  13

  •  17

  •  None of these

     
17Page 86

The equation of the plane through the intersection of the planes ax + by + cz + d = 0 andlx + my + nz + p = 0 and parallel to the line y=0, z=0

  • (bl − amy + (cl − anz + dl − ap = 0

  •  (am − blx + (mc − bnz + md − bp = 0

  •  (na − clx + (bn − cmy + nd − cp = 0

  • None of these

     
18Page 86

The equation of the plane which cuts equal intercepts of unit length on the coordinate axes is

  •  x + y + z = 1

  •  x + y + z = 0

  • x + y − z = 1

  •  x + y + z = 2

     

Solutions for 29: The Plane

Exercise 29.01Exercise 29.02Exercise 29.03Exercise 29.04Exercise 29.05Exercise 29.06Exercise 29.07Exercise 29.08Exercise 29.09Exercise 29.10Exercise 29.11Exercise 29.12Exercise 29.13Exercise 29.14Exercise 29.15Very Short AnswersMCQ
RD Sharma solutions for Mathematics [English] Class 12 chapter 29 - The Plane - Shaalaa.com

RD Sharma solutions for Mathematics [English] Class 12 chapter 29 - The Plane

Shaalaa.com has the CBSE, Karnataka Board PUC Mathematics Mathematics [English] Class 12 CBSE, Karnataka Board PUC solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. RD Sharma solutions for Mathematics Mathematics [English] Class 12 CBSE, Karnataka Board PUC 29 (The Plane) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.

Further, we at Shaalaa.com provide such solutions so students can prepare for written exams. RD Sharma textbook solutions can be a core help for self-study and provide excellent self-help guidance for students.

Concepts covered in Mathematics [English] Class 12 chapter 29 The Plane are Direction Cosines and Direction Ratios of a Line, Equation of a Line in Space, Shortest Distance Between Two Lines, Angle Between Two Lines, Overview of Three Dimensional Geometry.

Using RD Sharma Mathematics [English] Class 12 solutions The Plane exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in RD Sharma Solutions are essential questions that can be asked in the final exam. Maximum CBSE, Karnataka Board PUC Mathematics [English] Class 12 students prefer RD Sharma Textbook Solutions to score more in exams.

Get the free view of Chapter 29, The Plane Mathematics [English] Class 12 additional questions for Mathematics Mathematics [English] Class 12 CBSE, Karnataka Board PUC, and you can use Shaalaa.com to keep it handy for your exam preparation.

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