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Write the Angle Between the Line X − 1 2 = Y − 2 1 = Z + 3 − 2 and the Plane X + Y + 4 = 0.

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Question

Write the angle between the line \[\frac{x - 1}{2} = \frac{y - 2}{1} = \frac{z + 3}{- 2}\]  and the plane x + y + 4 = 0. 

 
Sum
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Solution

\[\text{ The given line is parallel to the vector }  \vec{b} = \hat{i}  + 2 \hat{j}  + 2 \hat{k}  \text{ and the given plane is normal to the vector }  \vec{n} = \hat{i}  + \hat{j}  + 0 \hat{k}  . \]

\[\text{ We know that the angle } \theta \text{ between the line and the plane is given by } \]

\[\sin \theta = \frac{\vec{b} . \vec{n}}{\left| \vec{b} \right| \left| \vec{n} \right|}\]

\[ = \frac{\left( \hat{i}  + 2 \hat{j}  + 2 \hat{k}  \right) . \left( \hat{i} + \hat{j}  + 0 \hat{k}  \right)}{\left| \hat{i}+ 2 \hat{j} + 2 \hat{k} \right| \left| \hat{i}  + \hat{j} + 0 \hat{k}  \right|} = \frac{1 + 2 + 0}{\sqrt{1 + 4 + 4} \sqrt{1 + 1 + 0}} = \frac{3}{3 \sqrt{2}} = \frac{1}{\sqrt{2}}\]

\[ \Rightarrow \theta = \sin^{- 1} \left( \frac{1}{\sqrt{2}} \right) = {45}^o \]

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Chapter 28: The Plane - Very Short Answers [Page 84]

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R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 28 The Plane
Very Short Answers | Q 17 | Page 84

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