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Find the Cartesian Form of the Equation of a Plane Whose Vector Equation is → R ⋅ ( − ^ I + ^ J + 2 ^ K ) = 9 - Mathematics

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Question

Find the Cartesian form of the equation of a plane whose vector equation is 

  \[\vec{r} \cdot \left( - \hat{i} + \hat{j}  + 2 \hat{k} \right) = 9\]

 

Sum
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Solution

`  \text{ Substituting }  \vec{r} =\text{ x }\hat{i}  +\text{  y }\hat{j}  +\text{  z }\hat{k}  \text{ in the given equation, we get } `
\[\left(  \text{ x }\hat{i}  +\text{ y }\hat{j}  + \text{  z }\hat{k}  \right) . \left( - \hat{i}  + \hat{j}  + \text{ 2 }\hat{k}  \right) = 9\]
\[ \Rightarrow - x + y + 2z = 9\]

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Chapter 29: The Plane - Exercise 29.03 [Page 13]

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RD Sharma Mathematics [English] Class 12
Chapter 29 The Plane
Exercise 29.03 | Q 2.2 | Page 13

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