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Find the Cartesian Form of the Equation of a Plane Whose Vector Equation is (I) → R ⋅ ( 12 ^ I − 3 ^ J + 4 ^ K ) + 5 = 0 - Mathematics

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Question

Find the Cartesian form of the equation of a plane whose vector equation is 

 \[\vec{r} \cdot \left( 12 \hat{i} - 3 \hat{j} + 4 \hat{k} \right) + 5 = 0\]

 

Sum
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Solution

` \text{ Substituting }  \vec{r} =\text{ x  }\hat{i} +\text{ y }\hat{j} + \text{ z }\hat{k} \text{ in the given equation, we get } `
\[\left( \text{ x }\hat{i} + \text{ y }\hat{j}  +\text{  z} \hat{k} \right) . \left( \text{ 12 }\hat{i} - \text{ 3 }\hat{j}  + 4 \hat{k} \right) + \text{ 5}= 0\]
\[ \Rightarrow 12x - 3y + 4z + 5 = 0\]

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Chapter 29: The Plane - Exercise 29.03 [Page 13]

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RD Sharma Mathematics [English] Class 12
Chapter 29 The Plane
Exercise 29.03 | Q 2.1 | Page 13

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