English

Find-vector-equation-plane-passing-through-point-a-b-c-parallel-plane-r-i-j-k-2 - Mathematics

Advertisements
Advertisements

Question

Find the vector equation of the plane, passing through the point (abc) and parallel to the plane \[\vec{r} . \left( \hat{i}  + \hat{j}  + \hat{k}  \right) = 2\]

 
Advertisements

Solution

The required plane passes through \[a \hat{i} + b \hat{j} + c \hat{k} \] and is parallel to the plane  \[\vec{r} . \left( \hat{i} + \hat{j} + \hat{k} \right) = 2\] So, it is normal to the vector  \[\hat{i}  + \hat{j} + \hat{k} \] which is normal to the given plane.
Hence, the vector equation of the required plane is

\[\left[ \vec{r} - \left( a \hat{i} + b \hat{j} + c \hat{k} \right) \right] . \left( \hat{i} + \hat{j} + \hat{k}  \right) = 0 \left[ \left( \vec{r} - \vec{a} \right) . \vec{n} = 0 \right]\]
\[ \Rightarrow \vec{r} . \left( \hat{i}  + \hat{j}  + \hat{k} \right) = \left( a \hat{i} + b \hat{j} + c \hat{k}  \right) . \left( \hat{i}  + \hat{j}  + \hat{k}  \right)\]
\[ \Rightarrow \vec{r} . \left( \hat{i}  + \hat{j}  + \hat{k}  \right) = a + b + c\]
Thus, the vector equation of the required plane is
\[\vec{r} . \left( \hat{i} + \hat{j} + \hat{k}  \right) = a + b + c\]
  
 
shaalaa.com
  Is there an error in this question or solution?
Chapter 29: The Plane - Very Short Answers [Page 84]

APPEARS IN

RD Sharma Mathematics [English] Class 12
Chapter 29 The Plane
Very Short Answers | Q 21 | Page 84

RELATED QUESTIONS

Find the equation of the plane passing through (abc) and parallel to the plane `vecr.(hati + hatj + hatk) = 2`


If the points (1, 1, p) and (−3, 0, 1) be equidistant from the plane `vecr.(3hati + 4hatj - 12hatk)+ 13 = 0`, then find the value of p.


Find the Cartesian form of the equation of a plane whose vector equation is 

  \[\vec{r} \cdot \left( - \hat{i} + \hat{j}  + 2 \hat{k} \right) = 9\]

 


Find the vector equations of the coordinate planes.

 

Find the vector equation of each one of following planes. 

2x − y + 2z = 8


Find the vector equation of each one of following planes. 

x + y − z = 5

 


Find the vector equation of each one of following planes. 

x + y = 3

 

Show that the normal vector to the plane 2x + 2y + 2z = 3 is equally inclined to the coordinate axes.

 

find the equation of the plane passing through the point (1, 2, 1) and perpendicular to the line joining the points (1, 4, 2) and (2, 3, 5). Find also the perpendicular distance of the origin from this plane


Find the vector equation of the plane passing through the points P (2, 5, −3), Q (−2, −3, 5) and R (5, 3, −3).


Determine the value of λ for which the following planes are perpendicular to each other.

\[\vec{r} \cdot \left( \hat{i}  + 2 \hat{j} + 3 \hat{k} \right) = 7 \text{ and }  \vec{r} \cdot \left( \lambda \hat{i} + 2 \hat{j}  - 7 \hat{k}  \right) = 26\]

 


Determine the value of λ for which the following planes are perpendicular to each ot

 2x − 4y + 3z = 5 and x + 2y + λz = 5


Find the equation of a plane passing through the point (−1, −1, 2) and perpendicular to the planes 3x + 2y − 3z = 1 and 5x − 4y + z = 5.

 

Obtain the equation of the plane passing through the point (1, −3, −2) and perpendicular to the planes x + 2y + 2z = 5 and 3x + 3y + 2z = 8.

 

Find the equation of the plane passing through the origin and perpendicular to each of the planes x + 2y − z = 1 and 3x − 4y + z = 5.

 

Find the vector equation of the line passing through the point (1, −1, 2) and perpendicular to the plane 2x − y + 3z − 5 = 0.

 

Find the coordinates of the point where the line through (5, 1, 6) and (3, 4, 1) crosses the  zx - plane .


Find the coordinates of the foot of the perpendicular drawn from the point (5, 4, 2) to the line \[\frac{x + 1}{2} = \frac{y - 3}{3} = \frac{z - 1}{- 1} .\]

 Hence, or otherwise, deduce the length of the perpendicular.

 
 

Find the coordinates of the foot of the perpendicular from the point (2, 3, 7) to the plane 3x − y − z = 7. Also, find the length of the perpendicular.


Find the length and the foot of perpendicular from the point \[\left( 1, \frac{3}{2}, 2 \right)\]  to the plane \[2x - 2y + 4z + 5 = 0\] .

 

Find the position vector of the foot of perpendicular and the perpendicular distance from the point P with position vector \[2 \hat{i}  + 3 \hat{j}  + 4 \hat{k} \] to the plane  \[\vec{r} . \left( 2 \hat{i} + \hat{j}  + 3 \hat{k}  \right) - 26 = 0\] Also find image of P in the plane.

 

Write the equation of the plane  \[\vec{r} = \vec{a} + \lambda \vec{b} + \mu \vec{c}\]   in scalar product form.

 

Write the equation of the plane passing through (2, −1, 1) and parallel to the plane 3x + 2y −z = 7.


Find the length of the perpendicular drawn from the origin to the plane 2x − 3y + 6z + 21 = 0.

 

Write the equation of a plane which is at a distance of \[5\sqrt{3}\] units from origin and the normal to which is equally inclined to coordinate axes.

 

The equation of the plane parallel to the lines x − 1 = 2y − 5 = 2z and 3x = 4y − 11 = 3z − 4 and passing through the point (2, 3, 3) is


Find a vector of magnitude 26 units normal to the plane 12x − 3y + 4z = 1.


If the line drawn from (4, −1, 2) meets a plane at right angles at the point (−10, 5, 4), find the equation of the plane.


Find the co-ordinates of the foot of perpendicular drawn from the point A(1, 8, 4) to the line joining the points B(0, –1, 3) and C(2, –3, –1).


Prove that the lines x = py + q, z = ry + s and x = p′y + q′, z = r′y + s′ are perpendicular if pp′ + rr′ + 1 = 0.


Find the length and the foot of perpendicular from the point `(1, 3/2, 2)` to the plane 2x – 2y + 4z + 5 = 0.


Find the equations of the line passing through the point (3, 0, 1) and parallel to the planes x + 2y = 0 and 3y – z = 0.


Find the equation of the plane through the points (2, 1, –1) and (–1, 3, 4), and perpendicular to the plane x – 2y + 4z = 10.


Show that the points `(hat"i" - hat"j" + 3hat"k")` and `3(hat"i" + hat"j" + hat"k")` are equidistant from the plane `vec"r" * (5hat"i" + 2hat"j" - 7hat"k") + 9` = 0 and lies on opposite side of it.


The locus represented by xy + yz = 0 is ______.


The point at which the normal to the curve y = `"x" + 1/"x", "x" > 0` is perpendicular to the line 3x – 4y – 7 = 0 is:


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×