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Question
Write the equation of the plane whose intercepts on the coordinate axes are 2, −3 and 4.
Sum
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Solution
\[\text{ We know that the equation of the plane with a, b and c intercepts on the coordianate axes is given by } \]
\[\frac{x}{a} + \frac{y}{b} + \frac{z}{c} = 1\]
\[\text{ Given that } \]
\[a = 2; b = - 3; c = 4\]
\[\text{ So, the equation of the required plane is } \]
\[\frac{x}{2} + \frac{y}{- 3} + \frac{z}{4} = 1\]
\[ \Rightarrow 6x - 4y + 3z = 12\]
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