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The Equation of Plane Containing the Two Lines X−1 2 = Y + 1 − 1 = Z − 0 3 a Nd X − 2 = Y − 2 − 3 = Z + 1 − 1 (A) 8x + Y − 5z − 7 = 0 (B) 8x + Y + 5z − 7 = 0 (C) 8x − Y − 5z − 7 = 0 (D) None of These - Mathematics

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Question

The equation of the plane containing the two lines

\[\frac{x - 1}{2} = \frac{y + 1}{- 1} = \frac{z - 0}{3} \text{ and }\frac{x}{- 2} = \frac{y - 2}{- 3} = \frac{z + 1}{- 1}\]
 
 

Options

  •  8x + y − 5z − 7 = 0

  •  8x + y + 5z − 7 = 0

  • 8x − y − 5z − 7 = 0

  •  None of these

     
MCQ
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Solution

 None of these

\[\frac{x - 1}{2} = \frac{y + 1}{-1} = \frac{z- 0}{3}\] and 

\[\frac{x}{- 2} = \frac{y - 2}{- 3} = \frac{z + 1}{- 1}\]

Now, if these two lines lie on a plane, so the direction ratio of lines will be perpendicular to the plane's normal vector.

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Chapter 29: The Plane - MCQ [Page 85]

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RD Sharma Mathematics [English] Class 12
Chapter 29 The Plane
MCQ | Q 6 | Page 85

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