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The Equation of the Plane Which Cuts Equal Intercepts of Unit Length on the Coordinate Axes is (A) X + Y + Z = 1 (B) X + Y + Z = 0 (C) X + Y − Z = 1 (D) X + Y + Z = 2

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Question

The equation of the plane which cuts equal intercepts of unit length on the coordinate axes is

Options

  •  x + y + z = 1

  •  x + y + z = 0

  • x + y − z = 1

  •  x + y + z = 2

     
MCQ
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Solution

 x + y + z = 1

 

\[\text{ We know that the equation of aplane whose intercepts are  a, b, c is }\]
\[\frac{x}{a} + \frac{y}{b} + \frac{z}{c} = 1 . . . \left( 1 \right)\]
\[\text{ It is given that  a = b = c } \]
\[\text{ So, from (1),} \]
\[\frac{x}{a} + \frac{y}{a} + \frac{z}{c} = 1 \]
\[ \Rightarrow x + y + z = a . . . (2)\]
\[\text{ Since it is given that the intercepts of the required plane are of unit length,} \]
\[a = b = c = 1\]
\[\text{ Substituting  a = 1 in (2), we get } \]
\[x + y + z = 1\]

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Chapter 28: The Plane - MCQ [Page 86]

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R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 28 The Plane
MCQ | Q 18 | Page 86
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