Chapters
Chapter 2: Polynomials
Chapter 3: Coordinate Geometry
Chapter 4: Linear Equation In Two Variables
Chapter 5: Introduction To Euclid's Geometry
Chapter 6: Lines & Angles
Chapter 7: Triangles
Chapter 8: Quadrilaterals
Chapter 9: Areas of Parallelograms & Triangles
Chapter 10: Circles
Chapter 11: Construction
Chapter 12: Heron's Formula
Chapter 13: Surface Area & Volumes
Chapter 14: Statistics & Probability

Chapter 1: Number Systems
NCERT solutions for Mathematics Exemplar Class 9 Chapter 1 Number Systems Exercise 1.1 [Pages 2 - 5]
Write the correct answer in the following:
Every rational number is ______.
A natural number
An integer
A real number
A whole number
Between two rational numbers ______.
There is no rational number
There is exactly one rational number
There are infinitely many rational numbers
There are only rational numbers and no irrational numbers
Decimal representation of a rational number cannot be ______.
Terminating
Non-terminating
Non-terminating repeating
Non-terminating non-repeating
The product of any two irrational numbers is ______.
Always an irrational number
Always a rational number
Always an integer
Sometimes rational, sometimes irrational
The decimal expansion of the number `sqrt(2)` is ______.
A finite decimal
1.41421
Non-terminating recurring
Non-terminating non-recurring
Which of the following is irrational?
`sqrt(4/9)`
`sqrt(12)/sqrt(3)`
`sqrt(7)`
`sqrt(81)`
Which of the following is irrational?
0.14
`0.14bar16`
`0.bar1416`
0.4014001400014...
A rational number between `sqrt(2)` and `sqrt(3)` is ______.
`(sqrt(2) + sqrt(3))/2`
`(sqrt(2) * sqrt(3))/2`
1.5
1.8
The value of 1.999... in the form `p/q`, where p and q are integers and q ≠ 0, is ______.
`19/10`
`1999/1000`
2
`1/9`
`2sqrt(3) + sqrt(3)` is equal to ______.
`2sqrt(6)`
6
`3sqrt(3)`
`4sqrt(6)`
`sqrt(10) xx sqrt(15)` is equal to ______.
`6sqrt(5)`
`5sqrt(6)`
`sqrt(25)`
`10sqrt(5)`
The number obtained on rationalising the denominator of `1/(sqrt(7) - 2)` is ______.
`(sqrt(7) + 2)/3`
`(sqrt(7) - 2)/3`
`(sqrt(7) + 2)/5`
`(sqrt(7) + 2)/45`
`1/(sqrt(9) - sqrt(8))` is equal to ______.
`1/2(3 - 2sqrt(2))`
`1/(3 + 2sqrt(2)`
`3 - 2sqrt(2)`
`3 + 2sqrt(2)`
After rationalising the denominator of `7/(3sqrt(3) - 2sqrt(2))`, we get the denominator as ______.
13
19
5
35
The value of `(sqrt(32) + sqrt(48))/(sqrt(8) + sqrt(12))` is equal to ______.
`sqrt(2)`
2
4
8
If `sqrt(2)` = 1.4142, then `sqrt((sqrt(2) - 1)/(sqrt(2) + 1))` is equal to ______.
2.4142
5.8282
0.4142
0.1718
`root(4)root(3)(2^2)` equals to ______.
`2^(-1/6)`
`2^-6`
`2^(1/6)`
`2^6`
The product `root(3)(2) * root(4)(2) * root(12)(32)` equals to ______.
`sqrt(2)`
2
`root(12)(2)`
`root(12)(32)`
Value of `root(4)((81)^-2)` is ______.
`1/9`
`1/3`
9
`1/81`
Value of `(256)^0.16 xx (256)^0.09` is ______.
4
16
64
256.25
Which of the following is equal to x?
`x^(12/7) - x^(5/7)`
`root(12)((x^4)^(1/3)`
`(sqrt(x^3))^(2/3)`
`x^(12/7) xx x^(7/12)`
NCERT solutions for Mathematics Exemplar Class 9 Chapter 1 Number Systems Exercise 1.2 [Page 6]
Let x and y be rational and irrational numbers, respectively. Is x + y necessarily an irrational number? Give an example in support of your answer.
Let x be rational and y be irrational. Is xy necessarily irrational? Justify your answer by an example.
State whether the following statement is True or False:
`sqrt(2)/3` is a rational number.
True
False
There are infinitely many integers between any two integers.
True
False
Number of rational numbers between 15 and 18 is finite.
True
False
There are numbers which cannot be written in the form `p/q, q ≠ 0`, p, q both are integers.
True
False
The square of an irrational number is always rational.
True
False
`sqrt(12)/sqrt(3)` is not a rational number as `sqrt(12)` and `sqrt(3)` are not integers.
True
False
`sqrt(15)/sqrt(3)` is written in the form `p/q, q ≠ 0` and so it is a rational number.
True
False
Classify the following numbers as rational or irrational with justification:
`sqrt(196)`
Classify the following numbers as rational or irrational with justification:
`3sqrt(18)`
Classify the following numbers as rational or irrational with justification:
`sqrt(9/27)`
Classify the following numbers as rational or irrational with justification:
`sqrt(28)/sqrt(343)`
Classify the following numbers as rational or irrational with justification:
`- sqrt(0.4)`
Classify the following numbers as rational or irrational with justification:
`sqrt(12)/sqrt(75)`
Classify the following numbers as rational or irrational with justification:
0.5918
Classify the following numbers as rational or irrational with justification:
`(1 + sqrt(5)) - (4 + sqrt(5))`
Classify the following numbers as rational or irrational with justification:
10.124124...
Classify the following numbers as rational or irrational with justification:
1.010010001...
NCERT solutions for Mathematics Exemplar Class 9 Chapter 1 Number Systems Exercise 1.3 [Pages 9 - 11]
Find which of the variables x, y, z and u represent rational numbers and which irrational numbers:
x2 = 5
Find which of the variables x, y, z and u represent rational numbers and which irrational numbers:
y2 = 9
Find which of the variables x, y, z and u represent rational numbers and which irrational numbers:
z2 = 0.04
Find which of the variables x, y, z and u represent rational numbers and which irrational numbers:
`u^2 = 17/4`
Find three rational numbers between –1 and –2
Find three rational numbers between 0.1 and 0.11
Find three rational numbers between `5/7` and `6/7`
Find three rational numbers between `1/4` and `1/5`
Insert a rational number and an irrational number between the following:
2 and 3
Insert a rational number and an irrational number between the following:
0 and 0.1
Insert a rational number and an irrational number between the following:
`1/3` and `1/2`
Insert a rational number and an irrational number between the following:
`(-2)/5` and `1/2`
Insert a rational number and an irrational number between the following:
0.15 and 0.16
Insert a rational number and an irrational number between the following:
`sqrt(2)` and `sqrt(3)`
Insert a rational number and an irrational number between the following:
2.357 and 3.121
Insert a rational number and an irrational number between the following:
0.0001 and 0.001
Insert a rational number and an irrational number between the following:
3.623623 and 0.484848
Insert a rational number and an irrational number between the following:
6.375289 and 6.375738
Represent the following numbers on the number line:
7
Represent the following numbers on the number line:
7.2
Represent the following numbers on the number line:
`(-3)/2`
Represent the following numbers on the number line:
`(-12)/5`
Locate `sqrt(5), sqrt(10)` and `sqrt(17)` on the number line.
Represent geometrically the following numbers on the number line:
`sqrt(4.5)`
Represent geometrically the following numbers on the number line:
`sqrt(5.6)`
Represent geometrically the following numbers on the number line:
`sqrt(8.1)`
Represent geometrically the following numbers on the number line:
`sqrt(2.3)`
Express the following in the form `p/q`, where p and q are integers and q ≠ 0:
0.2
Express the following in the form `p/q`, where p and q are integers and q ≠ 0:
0.888...
Express the following in the form `p/q`, where p and q are integers and q ≠ 0:
`5.bar2`
Express the following in the form `p/q`, where p and q are integers and q ≠ 0:
`0.bar001`
Express the following in the form `p/q`, where p and q are integers and q ≠ 0:
0.2555...
Express the following in the form `p/q`, where p and q are integers and q ≠ 0:
`0.1bar34`
Express the following in the form `p/q`, where p and q are integers and q ≠ 0:
0.00323232...
Express the following in the form `p/q`, where p and q are integers and q ≠ 0:
0.404040...
Show that 0.142857142857... = `1/7`
Simplify the following:
`sqrt(45) - root(3)(20) + 4sqrt(5)`
Simplify the following:
`sqrt(24)/8 + sqrt(54)/9`
Simplify the following:
`root(4)(12) xx root(7)(6)`
Simplify the following:
`4sqrt(28) ÷ 3sqrt(7) ÷ root(3)(7)`
Simplify the following:
`3sqrt(3) + 2sqrt(27) + 7/sqrt(3)`
Simplify the following:
`(sqrt(3) - sqrt(2))^2`
Simplify the following:
`root(4)(81) - 8root(3)(216) + 15root(5)(32) + sqrt(225)`
Simplify the following:
`3/sqrt(8) + 1/sqrt(2)`
Simplify the following:
`(2sqrt(3))/3 - sqrt(3)/6`
Rationalise the denominator of the following:
`2/(3sqrt(3)`
Rationalise the denominator of the following:
`sqrt(40)/sqrt(3)`
Rationalise the denominator of the following:
`(3 + sqrt(2))/(4sqrt(2))`
Rationalise the denominator of the following:
`16/(sqrt(41) - 5)`
Rationalise the denominator of the following:
`(2 + sqrt(3))/(2 - sqrt(3))`
Rationalise the denominator of the following:
`sqrt(6)/(sqrt(2) + sqrt(3))`
Rationalise the denominator of the following:
`(sqrt(3) + sqrt(2))/(sqrt(3) - sqrt(2))`
Rationalise the denominator of the following:
`(3sqrt(5) + sqrt(3))/(sqrt(5) - sqrt(3))`
Rationalise the denominator of the following:
`(4sqrt(3) + 5sqrt(2))/(sqrt(48) + sqrt(18))`
Find the values of a and b in the following:
`(5 + 2sqrt(3))/(7 + 4sqrt(3)) = a - 6sqrt(3)`
Find the values of a and b in the following:
`(3 - sqrt(5))/(3 + 2sqrt(5)) = asqrt(5) - 19/11`
Find the values of a and b in the following:
`(sqrt(2) + sqrt(3))/(3sqrt(2) - 2sqrt(3)) = 2 - bsqrt(6)`
Find the values of a and b in the following:
`(7 + sqrt(5))/(7 - sqrt(5)) - (7 - sqrt(5))/(7 + sqrt(5)) = a + 7/11 sqrt(5)b`
If `a = 2 + sqrt(3)`, then find the value of `a - 1/a`.
Rationalise the denominator in each of the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`4/sqrt(3)`
Rationalise the denominator in each of the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`6/sqrt(6)`
Rationalise the denominator in each of the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`(sqrt(10) - sqrt(5))/2`
Rationalise the denominator in each of the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`sqrt(2)/(2 + sqrt(2)`
Rationalise the denominator in each of the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`1/(sqrt(3) + sqrt(2))`
Simplify:
`(1^3 + 2^3 + 3^3)^(1/2)`
Simplify:
`(3/5)^4 (8/5)^-12 (32/5)^6`
Simplify:
`(1/27)^((-2)/3)`
Simplify:
`[((625)^(-1/2))^((-1)/4)]^2`
Simplify:
`(9^(1/3) xx 27^(-1/2))/(3^(1/6) xx 3^(- 2/3))`
Simplify:
`64^(-1/3)[64^(1/3) - 64^(2/3)]`
Simplify:
`(8^(1/3) xx 16^(1/3))/(32^(- 1/3))`
NCERT solutions for Mathematics Exemplar Class 9 Chapter 1 Number Systems Exercise 1.4 [Page 12]
Express `0.6 + 0.bar7 + 0.4bar7` in the form `p/q`, where p and q are integers and q ≠ 0.
Simplify: `(7sqrt(3))/(sqrt(10) + sqrt(3)) - (2sqrt(5))/(sqrt(6) + sqrt(5)) - (3sqrt(2))/(sqrt(15) + 3sqrt(2))`
If `sqrt(2) = 1.414, sqrt(3) = 1.732`, then find the value of `4/(3sqrt(3) - 2sqrt(2)) + 3/(3sqrt(3) + 2sqrt(2))`
If `a = (3 + sqrt(5))/2`, then find the value of `a^2 + 1/a^2`.
If `x = (sqrt(3) + sqrt(2))/(sqrt(3) - sqrt(2))` and`y = (sqrt(3) - sqrt(2))/(sqrt(3) + sqrt(2))`, then find the value of x2 + y2.
Simplify: `(256)^(-((-3)/4^2))`
Find the value of `4/((216)^(-2/3)) + 1/((256)^(- 3/4)) + 2/((243)^(- 1/5))`
Chapter 1: Number Systems

NCERT solutions for Mathematics Exemplar Class 9 chapter 1 - Number Systems
NCERT solutions for Mathematics Exemplar Class 9 chapter 1 (Number Systems) include all questions with solution and detail explanation. This will clear students doubts about any question and improve application skills while preparing for board exams. The detailed, step-by-step solutions will help you understand the concepts better and clear your confusions, if any. Shaalaa.com has the CBSE Mathematics Exemplar Class 9 solutions in a manner that help students grasp basic concepts better and faster.
Further, we at Shaalaa.com provide such solutions so that students can prepare for written exams. NCERT textbook solutions can be a core help for self-study and acts as a perfect self-help guidance for students.
Concepts covered in Mathematics Exemplar Class 9 chapter 1 Number Systems are Introduction of Real Number, Concept of Irrational Numbers, Real Numbers and Their Decimal Expansions, Representing Real Numbers on the Number Line, Operations on Real Numbers, Laws of Exponents for Real Numbers.
Using NCERT Class 9 solutions Number Systems exercise by students are an easy way to prepare for the exams, as they involve solutions arranged chapter-wise also page wise. The questions involved in NCERT Solutions are important questions that can be asked in the final exam. Maximum students of CBSE Class 9 prefer NCERT Textbook Solutions to score more in exam.
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