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Question
Simplify:
`(1^3 + 2^3 + 3^3)^(1/2)`
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Solution
`(1^3 + 2^3 + 3^3)^(1/2) = (1 + 8 + 27)^(1/2)` ...[∵ (am)n = amn]
= `(36)^(1/2)`
= `(6^2)^(1/2)`
= `6^(2 xx 1/2)`
= 6
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