Advertisements
Advertisements
Question
Simplify:
`(1^3 + 2^3 + 3^3)^(1/2)`
Advertisements
Solution
`(1^3 + 2^3 + 3^3)^(1/2) = (1 + 8 + 27)^(1/2)` ...[∵ (am)n = amn]
= `(36)^(1/2)`
= `(6^2)^(1/2)`
= `6^(2 xx 1/2)`
= 6
APPEARS IN
RELATED QUESTIONS
If a = 3 and b = -2, find the values of :
(a + b)ab
Show that:
`(x^(a^2+b^2)/x^(ab))^(a+b)(x^(b^2+c^2)/x^(bc))^(b+c)(x^(c^2+a^2)/x^(ac))^(a+c)=x^(2(a^3+b^3+c^3))`
Show that:
`(a^(x+1)/a^(y+1))^(x+y)(a^(y+2)/a^(z+2))^(y+z)(a^(z+3)/a^(x+3))^(z+x)=1`
If a and b are different positive primes such that
`(a+b)^-1(a^-1+b^-1)=a^xb^y,` find x + y + 2.
If 3x-1 = 9 and 4y+2 = 64, what is the value of \[\frac{x}{y}\] ?
Write the value of \[\sqrt[3]{125 \times 27}\].
The value of \[\left\{ 2 - 3 (2 - 3 )^3 \right\}^3\] is
If 102y = 25, then 10-y equals
If \[\frac{x}{x^{1 . 5}} = 8 x^{- 1}\] and x > 0, then x =
Simplify:-
`(1/3^3)^7`
