Advertisements
Advertisements
Question
Simplify:
`(1^3 + 2^3 + 3^3)^(1/2)`
Advertisements
Solution
`(1^3 + 2^3 + 3^3)^(1/2) = (1 + 8 + 27)^(1/2)` ...[∵ (am)n = amn]
= `(36)^(1/2)`
= `(6^2)^(1/2)`
= `6^(2 xx 1/2)`
= 6
APPEARS IN
RELATED QUESTIONS
If a = 3 and b = -2, find the values of :
ab + ba
Solve the following equation for x:
`2^(x+1)=4^(x-3)`
Solve the following equation for x:
`2^(5x+3)=8^(x+3)`
Given `4725=3^a5^b7^c,` find
(i) the integral values of a, b and c
(ii) the value of `2^-a3^b7^c`
If 2x = 3y = 6-z, show that `1/x+1/y+1/z=0`
If `x=2^(1/3)+2^(2/3),` Show that x3 - 6x = 6
Determine `(8x)^x,`If `9^(x+2)=240+9^x`
Simplify:
`root(lm)(x^l/x^m)xxroot(mn)(x^m/x^n)xxroot(nl)(x^n/x^l)`
If \[x = \frac{\sqrt{5} + \sqrt{3}}{\sqrt{5} - \sqrt{3}}\] and \[y = \frac{\sqrt{5} - \sqrt{3}}{\sqrt{5} + \sqrt{3}}\] then x + y +xy=
Simplify:
`(3/5)^4 (8/5)^-12 (32/5)^6`
