Advertisements
Advertisements
Question
Simplify:
`(1^3 + 2^3 + 3^3)^(1/2)`
Advertisements
Solution
`(1^3 + 2^3 + 3^3)^(1/2) = (1 + 8 + 27)^(1/2)` ...[∵ (am)n = amn]
= `(36)^(1/2)`
= `(6^2)^(1/2)`
= `6^(2 xx 1/2)`
= 6
APPEARS IN
RELATED QUESTIONS
Simplify the following
`((4xx10^7)(6xx10^-5))/(8xx10^4)`
Prove that:
`(a^-1+b^-1)^-1=(ab)/(a+b)`
If 49392 = a4b2c3, find the values of a, b and c, where a, b and c are different positive primes.
Show that:
`(a^(x+1)/a^(y+1))^(x+y)(a^(y+2)/a^(z+2))^(y+z)(a^(z+3)/a^(x+3))^(z+x)=1`
If `x=2^(1/3)+2^(2/3),` Show that x3 - 6x = 6
If (x − 1)3 = 8, What is the value of (x + 1)2 ?
The product of the square root of x with the cube root of x is
If x = 2 and y = 4, then \[\left( \frac{x}{y} \right)^{x - y} + \left( \frac{y}{x} \right)^{y - x} =\]
\[\frac{5^{n + 2} - 6 \times 5^{n + 1}}{13 \times 5^n - 2 \times 5^{n + 1}}\] is equal to
If \[x = \frac{\sqrt{5} + \sqrt{3}}{\sqrt{5} - \sqrt{3}}\] and \[y = \frac{\sqrt{5} - \sqrt{3}}{\sqrt{5} + \sqrt{3}}\] then x + y +xy=
